A food product containing 82% moisture content is being frozen. Predict the specific heat of the product at -8 ° C when 82% of the air is frozen. The specific heat of the dry product is 2.5 kJ / (kg ° C). It is assumed that the specific heat of water at -10 ° C is the same as that of water at 0 ° C, and that the specific heat of ice follows the function Cp ice = 0.0062 T frozen + 2.0649. Cp of frozen product = answer J / kg ° C.
A food product containing 82% moisture content is being frozen. Predict the specific heat of the product at -8 ° C when 82% of the air is frozen. The specific heat of the dry product is 2.5 kJ / (kg ° C). It is assumed that the specific heat of water at -10 ° C is the same as that of water at 0 ° C, and that the specific heat of ice follows the function Cp ice = 0.0062 T frozen + 2.0649. Cp of frozen product = answer J / kg ° C.
Chemistry by OpenStax (2015-05-04)
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ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 27E: The addition of 3.15 g of Ba(OH)28H2O to a solution of 1.52 g of NH4SCN in loo g of water in a...
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A food product containing 82% moisture content is being frozen. Predict the specific heat of the product at -8 ° C when 82% of the air is frozen. The specific heat of the dry product is 2.5 kJ / (kg ° C). It is assumed that the specific heat of water at -10 ° C is the same as that of water at 0 ° C, and that the specific heat of ice follows the function Cp ice = 0.0062 T frozen + 2.0649.
Cp of frozen product = answer J / kg ° C.
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