A force of 7 lb is required to hold a spring stretched 9 in. beyond its natural length. How much work W is done in stretching it from its natural length to 15 in. beyond its natural length? According to Hooke's Law, the force required to maintain a spring stretched x units beyond its natural length is proportional to x. This means that f(x) = kx, for some constant k. 3 ft, we have 7 = -k. So k = 4 Since our spring is stretched 9 in., which is equal to Ib/ft.

A force of 7 lb is required to hold a spring stretched 9 in. beyond its natural length. How much work W is done in stretching it from its natural length to 15 in. beyond its natural length? According to Hooke's Law, the force required to maintain a spring stretched x units beyond its natural length is proportional to x. This means that f(x) = kx, for some constant k. 3 ft, we have 7 = -k. So k = 4 Since our spring is stretched 9 in., which is equal to Ib/ft.

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter2: Equations And Inequalities

Section2.7: More On Inequalities

Problem 44E

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