A gas with a volume of 640 mL at a pressure of 2.91 atm is allowed to expand to a volume of 3.58 L. What is the pressure in the container if the temperature remains constant? Be sure to enter a unit with your answer.

University Physics Volume 2
18th Edition
ISBN:9781938168161
Author:OpenStax
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Chapter2: The Kinetic Theory Of Gases
Section: Chapter Questions
Problem 81AP: One process for decaffeinating coffee uses carbon dioxide ( M=44.0 g/mol) at a molar density of...
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A gas with a volume of 640 mL at a pressure of 2.91 atm is allowed to expand to a volume of 3.58
L. What is the pressure in the container if the temperature remains constant? Be sure to enter a
unit with your answer.
Answer:
.052atm
If the pressure of a sample of gas is tripled under constant temperature, what will happen to the
volume?
Select one:
a. The volume will decrease by one-third.
b. The volume will triple.
c. The volume will be reduced by one-half.
d. The volume will double.
e. The volume will remain the same.
Clear my choice
If 173 mL of neon at 39.9 °C is allowed to expand to 422 mL, what must the new temperature be to
maintain constant pressure? Express your answer in °C. You do not need to enter units.
Answer:
1829.73
Transcribed Image Text:A gas with a volume of 640 mL at a pressure of 2.91 atm is allowed to expand to a volume of 3.58 L. What is the pressure in the container if the temperature remains constant? Be sure to enter a unit with your answer. Answer: .052atm If the pressure of a sample of gas is tripled under constant temperature, what will happen to the volume? Select one: a. The volume will decrease by one-third. b. The volume will triple. c. The volume will be reduced by one-half. d. The volume will double. e. The volume will remain the same. Clear my choice If 173 mL of neon at 39.9 °C is allowed to expand to 422 mL, what must the new temperature be to maintain constant pressure? Express your answer in °C. You do not need to enter units. Answer: 1829.73
Expert Solution
Step 1

Since there are multiple questions being posted, we are answering the first question.

As the temperature remains constant, the Boyle’s law is given by

P1V1=P2V2P2=P1V1V2

Substitute 2.91atm for P1640mL for V1, and  3.58L for V2 in the above equation.

P2=2.91atm640mL×10-3L1mL3.58L=0.520atm

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