A group of BET DMT students conducted an experiment on "Torques and Rotational Equilibrium" and obtained the following data: Table 1 Table 2 m1 = x1 = d1= T1 = Tccw = Percent Diff mo = Table 1 m1 = x1 = d1= T1 = Percent Diff 0.0997 0.1 kg m m N-m N-m % 0.07 4.00 0.10 0.10 m2 = x2 = d2= T2= kg Tcw = kg m N-m m % xg= m2 = x2 = d2= T2 = 0.1925 0.75 kg m m N-m N-m 0.50 0.19 0.70 m3 = x3 = d3= T3 = m kg m m N-m 0.0489 0.31 kg | m m N-m

Glencoe Physics: Principles and Problems, Student Edition
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Author:Paul W. Zitzewitz
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Chapter8: Rotational Motion
Section: Chapter Questions
Problem 82A
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A group of BET DMT students conducted an experiment on "Torques and Rotational Equilibrium" and obtained
the following data:
Table 1
Table 2
m1 =
x1 =
d1=
T1 =
Tccw =
Percent Diff
mo =
Table 1
m1 =
x1 =
d1=
T1=
Percent Diff
0.0997
0.1
kg
m
m
N-m
N-m
%
x1 =
m1 =
0.07
4.00
d1=
mo(exp)
0.10
0.10
Percent Error
m2 =
x2 =
Table 3
Support xo = 0.211
0.1925
d2 =
T2=
Tcw=
0.10
kg
kg
m
N-m
m
%
xg=
EEE
m2 =
x2 =
d2=
T2 =
0.1925
0.75
kg
EE
N-m
N-m
m2 =
x2 =
d2=
0.50
0.19
0.70
m3 =
x3 =
d3=
T3 =
0.50
m
kg
3
m
N-m
0.0489
0.31
kg
m
m
kg
%
kg
3
m
N-m
Transcribed Image Text:A group of BET DMT students conducted an experiment on "Torques and Rotational Equilibrium" and obtained the following data: Table 1 Table 2 m1 = x1 = d1= T1 = Tccw = Percent Diff mo = Table 1 m1 = x1 = d1= T1= Percent Diff 0.0997 0.1 kg m m N-m N-m % x1 = m1 = 0.07 4.00 d1= mo(exp) 0.10 0.10 Percent Error m2 = x2 = Table 3 Support xo = 0.211 0.1925 d2 = T2= Tcw= 0.10 kg kg m N-m m % xg= EEE m2 = x2 = d2= T2 = 0.1925 0.75 kg EE N-m N-m m2 = x2 = d2= 0.50 0.19 0.70 m3 = x3 = d3= T3 = 0.50 m kg 3 m N-m 0.0489 0.31 kg m m kg % kg 3 m N-m
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