A hörizontal curve is being designed for ew two-lane highway (3.6-m lanes). The PI is at station 7 + 640, the design speed is 105 km/h, and a maximum superelevation of 0.08 m/m is to be used. If the central angle of the curve is 35 degrees, design a curve for the

A hörizontal curve is being designed for ew two-lane highway (3.6-m lanes). The PI is at station 7 + 640, the design speed is 105 km/h, and a maximum superelevation of 0.08 m/m is to be used. If the central angle of the curve is 35 degrees, design a curve for the

Traffic and Highway Engineering

5th Edition

ISBN:9781305156241

Author:Garber, Nicholas J.

Publisher:Garber, Nicholas J.

Chapter15: Geometric Design Of Highway Facilities

Section: Chapter Questions

Problem 21P

See similar textbooks

Related questions

Q: 5. A compound curve is joined by two simple curves adjacent to each other, the first one having a…

A: given - compound curve is formed by joining 2 simple curve first curve - radius = 200m, central…

Q: Design a horizontal curve for the highway by computing the radius and stationing of PC and PT using…

A: Horizontal curve: A horizontal curve is a curve that provides the transition between two tangent…

Q: A two-lane highway (one 3.6-m lane in each direction) with a design speed of 100 km/h goes from…

Q: In a parabolic vertical curve, if the rising grade is 2% followed by a downgrade of 2%, and the rate…

Q: A 5° curve diverges from a 3° main curve in the reverse direction in the layout of a broad gauge…

A: Solution Given Data V=35 kmph

Q: A vertical curve is to be design to joint (+3) percent grade with a (-3.5) percent grade, sight…

A: It is required to determine the minimum length of the curve. Assume S < L L=AS21002h1+2h22 Here A…

Q: A parabolic sag curve has a sight distance of 118 m. the tangent grades of the curve are -3% and…

A: Given Data Sight distanceS=118 mThe gradients are N1=-3%N2=5% Here it is asked to calculate the…

Q: Q7.An equal-tangent vertical curve is to be constructed between grades of -2.0% and +1.0%. The PVI…

A: Step 1

Q: A circular road having curve of 8o curvature is to be 6 m. wide on the tangents and 6.75 m. wide…

A: Draw the figure i.) The expression for P.C at inner edge is given as P.C at inner edge=P.C at…

Q: For a sag vertical curve, (g1= -2.5%), (g2=+2.9%), the design speed (55 mile/hr.). The minimum…

Q: A vertical parabolic curve is to be used under a grade separation structure. The minus grade left to…

Q: In a parabolic vertical curve, if the rising grade is 2% followed by a downgrade of 2%, and the rate…

Q: 2. A vertical parbolic curve was design in order to have a clear sight distance of 120 m. The grade…

A: Given: Sight Distance= 120 m Grade lines intersection Station = 9+000 Elevation = 160.50 m…

Q: A 400-ft equal-tangent sag vertical curve has its PVC at station 78+00 and elevation 800 ft. The…

A: Length of curve (L) = 400 ftStation of PVC = 78+00Elevation of PVC = 800 ft

Q: Please show illustration if possible. A compound curve has a length of the chord of the first curve…

Q: A vertical parbolic curve was design in order to have a clear sight distance of 120 m . The grade…

A: sing relation for SSDSSD=vt+v22gf±Gf=0.35G=0.05t=2.5sec

Q: Q3: A horizontal curve is to be designed for a two-lane road in mountainous terrain. The following…

A: Given Data: The intersection angle of the curve is, ∆=30° The tangent length of the curve is, T=150…

Q: For a sag vertical curve, (g1= -2.5%), (g2=+2.9%), the design speed (55 mile/hr.). The minimum…

Q: A horizontal curve on a two-lane highway has its PC at station 123+70 and its PI at station 130+90.…

Q: Determine the length of total curve, L2 and the maximum offset (H)

Q: A vertical curve of 1,000-ft is designed to connect a grade of +4% to a grade of -5%. The V.P.I, is…

Q: A vertical curve of 600 ft connects a +4% grade to a -2% grade. The elevation of the V.P.C. is 1,250…

Q: Q5; Calculate the length of a transition curve for a B.G. curved track having 5° & a cant of 18 cm.…

Q: A compound curve has vertex angles of the first and second curve of 12°30' and 09°30', respectively.…

Q: Q2: Determine the minimum length of the curve between - 0.7% grade and a +0.5% grade for a road with…

A: Design speed=110kmph Headlight distance=220m To find minimum length of curve

Q: For a sag vertical curve , (g1= -2.5%), (g2=+2.9%), the design speed (55 mile/hr.). The minimum…

A: Given data Grade 1, g1=-2.5% Grade 2, g2=2.9% Design speed=55mi/hr

Q: A 400-ft equal-tangent sag vertical curve has its PC at station 100 + 00 and elevation 500 ft. The…

A: The curve with vertical alignment which is build while gradients with two different value meet is…

Q: On a two-lane road with 12-ft lanes, a horizontal curve is designed for 50 mi/h with a…

A: Given data: 12 ft- two lane road Superelevation = 10% PI= 220+48 PC= 216+74 speed= 50mile/hr fs=…

Q: a. The length of the second curve in ft given that the design speed of the first curve is 80 kph…

Q: For the curve above, (an equal- tangent vertical curve connects a +3.2 % and a -1.1 % grade. The PVI…

Q: A- A horizontal curve is required to connect two tangents of a road with deflection angle of 50°…

A: Horizontal curves are circular curves that are provided for changing the direction or the alignment…

Q: A compound curve has vertex angles of the first and second curve of 12°30' and 09°30', respectively.…

A: Given Data:Vertex Angle = 12°30'and 09°30'Degree of curve = 3°30' and 4°00'

Q: A symmetrical parabolic curve connects two grades of +6% and -4%. It is to pass through a point "A",…

A: Grades of parabolic curve are = +6% and -4% Elevation = 198.13 m Elevation at grade intersection=…

Q: A compound curve has vertex angles of the first and second curve of 12°30' and 09°30', respectively.…

Q: 2. A vertical parbolic curve was design in order to have a clear sight distance of 120 m. The grade…

Q: Compute the minimum radius of horizontal curve for a design speed of 80 kph. f = 0.15, e = 0.067.

Q: A section of a two high way has 12fl lanes and a design speed of 75m/h. The section contains a…

A: Solution: Given Data: Speed=75 mph=110…

Q: An equal tangent sag vertical curve is designed for 45 mi/h. The low point is at station 112+37…

Q: An unsymmetrical parabolic curve has a forward tangent of -8% and a back tangent of +5%. The length…

A: For Unsymmetrical vertical curve we haveClearance=Difference between elevation of Intersection of…

Q: Q6. To help improve the safety of at-grade intersection of two roads, the intersection is being…

A: Given Data, G1=+4% (Upgrade)G2= -3% (Downgrade)L1= 138 mStation PVC1=14+47, Elevation PVC1=477m…

Q: 1. A sag vertical curve is shown below: BVC Sta 19+50 EVC Sta 24+50 -3.2% +2.4% EVİ Sta 22+00; Elev…

A: Hi! Thank you for the question As per the honor code, We’ll answer the first question since the…

Q: An equal-tangent sag vertical curve is designed with the PVC at station 109 + 00 and elevation 950…

A: Procedure: In order to find the solution, we need to find the initial grade. After that, we need to…

Q: JA horizontal curve on a two-lane highway (12-ft lanes) has PC at station 124 + 00 and PT at station…

A: Horizontal curves: The curve provides a transition between two tangent strips of the roadway,…

Q: Problem no. 3: Two simple curves having angles of intersection of the tangents equal to 69° and 42°…

Q: A symmetrical parabolic summit curve connects two grades of +6% and -4%. It is to pass through a…

A: “Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…

Q: A simple curve has a radius of 286.48 m. Its distance from BC to EC along the curve is equal to 240…

Q: You are asked to design a horizontal curve with a 40-degree central angle (A=40) for a two-lane road…

Q: A section of a two-lane highway (one lane in each direction) (12-ft lanes) is designed for 55 mi/h.…

A: Given- V=55mi/hG1=-2.9%G2=+1.8%PVT=38+50e=0.08∆=39°

Q: A 3.5˚ curve is to be designed on a highway with a design speed of 60 mi/h. Spiral transition curves…

Concept explainers

Curve setting

A curve is a turn that is provided horizontally or vertically in the design of highways, railways, and runways. A curve connects two straight lines that are separated by the deflection angle. It helps to change the direction and alignment of the highways, railway tracks, and runways. Therefore, the gradual change in their alignment is made by using a curve to provide comfort to the passengers and this also provides an easy turn to change the direction of the moving vehicle.

Question

A horizontal curve is being designed for a new two-lane highway (3.6-m lanes).
The PI is at station 7 + 640, the design speed is 105 km/h, and a maximum superelevation of
0.08 m/m is to be used. If the central angle of the curve is 35 degrees, design a curve for the
highway by computing the radius and stationing of the PC and PT.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Trending now

This is a popular solution!

Step by step

Solved in 4 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

A two-lane highway (one 3.6-m lane in each direction) with a design speed of 100 km/h goes from normal crown with 2% cross-slope to 6 % superelevation by means of a spiral transition curve. The spiral curve is 60m long. If the superelevation is attained by rotating the road section around its centreline, draw a cross section of the road at 10, 20 and 50m from TS
A horizontal curve has a maximum speed of 50 mph. If e = 0.10, and f = 0.16, find the degree of the curve. a. 4.84 deg b. 5.84 deg c. 3.84 deg d. 6.24 deg
The ascending of a vertical curve is 1/45 and descending gradient is 1/55. If the design speed is 60 km/hr and rate of change of acceleration of 0.4 m/s3, calculate the minimum length of the curve.
A 200-m symmetrical parabolic curve is to be placed between grades of g1=1.25% and g2=-2.75% intersecting at station 18+000, which has an elevation of 270.190m above mean sea level. a)Calculate elevations for every 20-m station on the vertical curve b)Determine the station and elevation of the highest point on the curve. c)Determine the rate of change of the vertical curve.
An equal-tangent crest vertical curve is designed with a PVI at station 110 + 00 (elevation 927.2 ft) and a PVC at station 107 + 43.3 (elevation 921.55 ft). If the high point is at station 110 + 75.5, what is the design speed of the curve?
An unsymmetrical parabolic curve has a forward tangent of 10% and a back tangent of +6%. the length of the curve on the left side (P.C) is 60m. If the vertex is at elevation of 100 m and the rate of change in grade of the first curve is -2% per 20m length, determine the following: A. Elevation of P.C. B. Elevation of P.T. C. Length of the Second Curve
A vertical parabolic curve has a back tangent of -5% and a forward tangent of +3% intersecting at station 1 + 240 at an elevation of 100.00 m. If the stationing of P.C. is at 1 + 120. Evaluate the stationing of the lowest point in the curve. Evaluate the elevation of the lowest point in the curve. Evaluate the rate of change of grade of the sag curve per 20 m length.
Find the minimum distance between the points of intersections (PI to PI) for two reversing horizontal curves, R = 6010 ft for both curves, on a 6-lane (total) Freeway with 80 mph design speed. The axis of rotation is about the centerline. The first curve has a delta of 36°and the second curve has a delta of 28° degrees. Note: distance from axes of rotation to the outside edge of lane = 46 ft
Q3: A horizontal curve is to be designed for a two-lane road in mountainous terrain.The following data are known: Intersection angle: 30 degrees, tangent length = 150 m,station of PI: 2+750.000, fs = 0.10, e = 0.08.
Given two grades intersecting at station 1 + 250m, one grade at +6%, the other at -3%. Use a vertical curve of 183m composed of two sections, L1 of 121.95m and L2 of 61.05m. Find the elevation on the curve at station 1 + 220 and at station 1 + 280.
A compound curve has vertex angles of the first and second curve of 12°30' and 09°30', respectively. Stationing at the point of compound curve is at 11+135.92m. Degrees of curve are 3°00' and 4°00' for the first and second curve, respectively. It is desired to substitute the compound curve with a simple curve that shall end with the same P.C. Determine the: a. Total length of the simple curve b. Station the Old P.C. and the New P.T.
A simple curve having a degree of curve equal to 40030’ has a central angle of 50050’. It is required to replace the simple curve with another circular curve y connecting a transition curve (spiral) at each ends by maintaining the radius of the old curve and the center of the new central curve is moved away by 5 m. from the intersection point. Determine the central angle of the circular curve Compute the tangent distance Ts of the spiral curve What is the maximum velocity that a car could pass thru curve without skidding?