a) How many bits are in a virtual address? b) How many bits are in a physical address? c) What physical address corresponds to the following virtual addresses? (If the address causes a page fault, simply indicate this is the case.) i. Ох0 ii. Ox44 iii. OxC2 iv. Ox80
Q: Given a 32-bit virtual address space and a 24-bit physical address, determine the number of bits in…
A: As given a 32-bit virtual address space and a 24-bit physical address, determination the number of…
Q: I need an answer to question no. 2
A: Assuming the page size to be 4KB. The calculations for physical addresses are given below: (a) VA =…
Q: 2) Assuming X22 has 7000, what address will be stored in X9 by: LDUR X9, (X22, #7] a) 7000 b) 7007…
A: According to the information given:- we have to find out the correct option on the basic of LDUR X9,…
Q: he contents of the following registers are: CS = 2212 H DS = 4040 H SS = 3025 H IP = 2230 H SP =…
A: We are going to find out physical addresses of CS,DS, and SS. I have uploaded image for the solution…
Q: Suppose you have a byte-addressable virtual address memory system with eight virtual pages of 64…
A: Answer: 1. Since it is be addressable, each page consists of 8 bits(i.e 1byte).It consists…
Q: 2. A system that uses a two-level page table has 212-byte pages and 32 -bit virtual addresses. The…
A: Given: -
Q: A very old computer had 24-bit addresses and 4KB pages. How many virtual address bits were occupied…
A: Solution: Given, Virtual memory system = 24-bit Page size = 4 KB
Q: 1. Assume data block can hold 512 Bytes and iNode has 10 direct pointers. 11 th point is a single…
A: Answer: Given Data Block Can hold 512 Bytes and I node has 10 Direct pointer 11th Single Indirect…
Q: multi-level paging used by a process that has following: a. Logical Address = 64 bits b. Page size…
A: A. Logical address bits is 64 So logical address space is 264 B B. One page table entry size = 4B…
Q: Assume we have a program that resides in the memory range of 80088000-820FOF00. The numbers are in…
A: a. PAGE SIZE(in bytes) = 2^offset = 2^8 = 256Bytes b. Number of entries in 1st level page table is =…
Q: Give the number of the virtual page that the byte with virtual memory address 52000 belongs to,…
A: Page size = 8KiB This means page offset = log 8KiB = 13 bits So the least significant 13 bits will…
Q: Suppose we want a segment to start at physical memory address 100 and have 200 memory locations.…
A: Relocation register: It contains the offset value which is added to the logical address to obtain…
Q: How many bits are in a physical address?
A: There are 4 pages frames of size 64 each, or 22 x 26=28. So each physical address has 8 bits.
Q: Consider a logical address of 128 pages of 1024 words each, mapped onto a physical memory of 64…
A: Hey there, I am writing the required solution based on the above given question. Please do find the…
Q: a simple paging system with 224 bytes of physical memory, 256 pages of logical address space, and a…
A: Given : Physical memory = 224 bytes Logical address space = 256 pages Page size = 210 bytes
Q: Consider a logical address space of 256 pages with a 4-KB page size, mapped onto a physical memory…
A: The answer is as follows.
Q: 2. Consider the following assumptions: Size of virtual address: 64 bits Size of physical address: 29…
A: Find the required answer with calculation given as below :
Q: Convert the physical addresses to logical using the combined paging segmentation scheme 256 Physical…
A: From the given memory:Therefore, 32 bytes given. Seg No. No. of pages Size Pages 1…
Q: ry split into pages. If each byte in the virtual memory has a virtual address, and the last 8 bits…
A: Pages are typically 512 to 8192 bytes in size, with 4096 being the most common value. For reasons…
Q: For the following problems assume 1 kilobyte (KB) = 1024 bytes and1 megabyte (MB) = 1024 kilobytes.…
A: Below is the answer to abobe question. I'm providing the answr to all su
Q: If logical addresses are represented using m bits as shown below, where m=4 and n=2. What is the…
A: Actually, memory is used to stores the data.
Q: Suppose a computer using direct-mapped cache has 232 bytes of byte-addressable main memory and a…
A: A cache is an equipment or programming segment that stores information so future solicitations for…
Q: Suppose a computer using direct mapped cache has 4G Bytes of main memory and a cache of 256 Blocks,…
A: refer to step 2 for the answer.
Q: What constitutes a virtual address's components (fields)?
A: Given: What constitutes a virtual address's components (fields)?
Q: 1- What is the physical address of the last memory location in the 8086 Mp (IMByte) memory? What…
A: In this question we are discussing about the 8086 micro pricessor
Q: Assume a 32-bit virtual address and 4 MBs of memory (i.e., DRAM). If the page size is 1 KB, then…
A: Assume a 32-bit virtual address and 4 MBs of memory (i.e., DRAM). If the page size is 1 KB, then…
Q: 1.What is the difference between bit address 7CH and byte address7CH? What is the specific location…
A: Dear Student, The main difference between bit and byte address is bit address ie represented by each…
Q: Question 1 In every address block, there are two reserved addresses. Which ones are those addresses?…
A: The answer is
Q: Suppose a computer using fully associative cache has 224 bytes of byte-addressable main memory and a…
A: To find the solution for given question: How many blocks of main memory are there? What is the…
Q: Suppose that an MMU has page table entries like the ones shown at right (formatted as in the slides…
A: The solution of the above question is:
Q: CA_10 Let the virtual address be V bits and the virtual addtess space be byte-addressable, the page…
A: Note: Answering the first three subparts as per the guidelines. Given : Virtual address bits = V…
Q: 6. Consider a logical address space of 16 pages of 2048 words each, mapped onto a physical memory of…
A: Given that, Logical address of 16 pages of 2048 words each. Number of physical memory frames= 4
Q: Figure below refers to memory management using paging. The logical address space (left) and page…
A: ans is given below
Q: Assume you have a small virtual address space of size 2048 KB, and that the system uses paging, but…
A: Below is the answer to the above question. I hope this will meet your requirement.
Q: Given the 128K page size associated with the 1GB address space, calculate the number of pages in the…
A: Here in this question we have given virtual address space =1GB. Page size= 128kb Physical address…
Q: When a Page Fault is encountered during a Virtual Address translation to Physical Address, either…
A: When a page fault occur , exception is raised by hardware when a running program accesses a memory…
Q: Suppose a computer using direct mapped cache has 232 words of main memory, and a cache of 1024…
A: Given: Suppose a computer using a direct-mapped cache has 232 words of main memory and a cache of…
Q: If the size of logical address space is 2 to the power of m, and a page size is 2 to the power of n…
A: If the size of logical address space is 2 to the power of m, and a page size is 2 to the power of…
Q: For the following problems assume 1 kilobyte (KB) = 1024 bytes and 1 megabyte (MB) = 1024 kilobytes.…
A: Below is the answer to above question. I hope this will be helpful for you...
Q: Consider a logical address space of 256 pages with a 4-KB page size, mapped onto a physical memory…
A: According to the Question below the Solution:
Q: Q3 The program size = 16, and page size 2^2, find the physical address in the following: 1) page 0…
A: Answer
Q: b) Assuming a 1024 byte page size, what are the page numbers and offsets for the following address…
A: Formulas Used: page number= logical address / page size Offset = logical address mod page size=…
Q: Q3: If page in logical address space consists of 32 words. And the size of that address is 12 bits,…
A:
Q: Let the virtual address be V bits and the virtual addtess space be byte-addressable, the page size…
A: D) Total number of virtual memory bits to be translated is V bits.
Q: Assume a 32-bit address system that uses a paged virtual memory, with a page size of 2 KB, and a PTE…
A: Data given in the question, 32-bit address system page size of 2 KB PTE (Page Table Entry) size of 1…
Q: For the following problems assume 1 kilobyte (KB) 1024 kilobytes 1024 bytes and 1 megabyte (MB) For…
A: For solving this question, a user must know the meaning of the virtual address and the use of a…
Q: Assume a logical address space consists of 4 pages of 4096 words each and is mapped to a physical…
A: logical address space consists of 4 pages of 4096 words 256 frames
Q: Describe the complete process of how address subblocks are designed and support the description by…
A: Q1. The given IP address is 10 10.10.10.0 /27 Here /27 means # of network ID bits is 27. Therefore…
Q: Assume you have a small virtual address space of size 2048 KB, and that the system uses paging, but…
A:
Q: the following. All numbers are decimal, everything is numbered starting from zero, and all addresses…
A: (a) The specified virtual address is V. Page number (P) = (virtual address) / (page size) Page…
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- Assume a 32-bit address system that uses a paged virtual memory, with a page size of 2 KB. Answer the following questions, assuming a virtual address 0x00030f40 A. What is the virtual page number (VPN) and the offset in binary for the given virtual address? B. How many virtual pages are there in the system?Question 12 Suppose you have a byte-addressable virtual address memory system with 8 virtual pages of 64 bytes each, and 4 page frames. a. How many bytes are in a virtual address? b. How many bytes are in a physical address?1. Consider a computer system with a 30-bit logical address and 4-KB page size. The systemsupports up to 512 MB of physical memory. How many entries are there in each of the following?Assume that each page table entry is 4 Bytes.c. A conventional single-level page table?d. An inverted page table?e. A two-level hierarchical page table? 2. Consider a virtual memory system with a 50-bit logical address and a 38-bit physical address.Suppose that the page/frame size is 16K bytes. Assume that each page table entry is 4 Bytes.a. How many frames are in the systems? How many pages in the virtual address space for aprocess?b. If a single-level page table is deployed, calculate the size of the page table for each process.c. Design a multilevel page table structure for this system to ensure that each page table can fitinto one frame. How many levels do you need? Draw a figure to show your page systems
- Suppose you have a byte-addressable virtual address memory system with 16 virtual pages of 64 bytes each and 4-page frames. Assuming the following page table, answer the questions below: Page # Frame # Valid bit 0 2 1 1 3 1 2 - 0 3 0 0 4 1 1 5 - 0 6 - 0 7 - 0 a) Show the virtual address format, including the name and size of the fields. b) Show the physical address format, including the name and size of the fields. c) What physical address corresponds to the virtual address 0x00? Answer should be in hexadecimal number. (if the address causes a page fault, answer as "page fault" with the proper explanation) d) What physical address corresponds to the virtual address 0x42? Answer should be in hexadecimal number. (if the address causes a page fault, answer as "page fault" with the proper explanation) e) What physical address corresponds to the virtual address 0x72? Answer should be in hexadecimal number. (if the address causes a page fault, answer as "page…Assume a 32-bit address system that uses a paged virtual memory, with a page size of 2 KB, and a PTE (Page Table Entry) size of 1 B. Answer the following questions, assuming a virtual address 0x00030f40 a. What is the virtual page number (VPN) and the offset in binary for the given virtual address? b. How many virtual pages are there in the system?Suppose a computer system uses 16-bit addresses for both its virtual and physical addresses. In addition, assume each page (and frame) has size 256 bytes. Could you hand draw the page table, if possible a) Suppose that the OS uses a two-level page table. Draw the page table. (Assume that frames 7 through 221 are free, so you can allocate space for the page table there.) In addition, suppose that the page-table directory storage comprises a whole number of consecutive full frames. (For examples: if the directory entry is 2 bytes, the entry’s storage comprises 1 frame; if the directory entry is 260 bytes, the entry’s storage comprises 2 consecutive frames.) b) What is the size of the two-level page table
- Consider a computer system with a 64-bit logical address and 32-KB page size. Thesystem supports up to 4096 MB of physical memory. How many entries are there ineach of the following?a. A conventional single-level page table?b. An inverted page table?Suppose that a machine has 42-bit virtual addresses and 32-bit physical addresses.{a} How much RAM can the machine support (each byte of RAM must be addressable)?{b} What is the largest virtual address space that can be supported for a process?{c} If pages are 2 KB, how many entries must be in a single-level page table?{d} If pages are 2 KB and we have a two-level page table where the first level is indexed by 15-bits, then how many entries does the first-level page table have?{e} With the same setup as part {d}, how many entries are in each second-level page table?{f} What is the advantage of using a two-level page table over single-level page table?Suppose you have a byte-addressable virtual address memory system with 32 virtual pages of 32 bytes each, and 8 page frames. Assuming the following page table, answer the questions below: | Page # | Frame # | Valid bit ||--------|---------|-----------|| 0 | 4 | 1 || 1 | 3 | 1 || 2 | - | 0 || 3 | 0 | 0 || 4 | 1 | 1 || 11 | 6 | 0 || 13 | 7 | 1 || 17 | - | 0 | a) How many bits are needed to address this virtual memory? b) What is the size of the Page field? c) What is the size of the Offset field? d) What is the size of the Page Frame field? e) What is the maximum number of the entries in this Page Table? f) What Physical address corresponds to the Virtual address 0x22? Answer should be in hexadecimal number. (if the address causes a page fault, answer as "page fault" with the proper reason) g) What Physical address corresponds to the…
- Suppose you have a byte-addressable virtual address memory system with 32 virtual pages of 32 bytes each, and 8 page frames. Assuming the following page table, answer the questions below: | Page # | Frame # | Valid bit ||--------|---------|-----------|| 0 | 4 | 1 || 1 | 3 | 1 || 2 | - | 0 || 3 | 0 | 0 || 4 | 1 | 1 || 11 | 6 | 0 || 13 | 7 | 1 || 17 | - | 0 |a) How many bits are needed to address this virtual memory? b) What is the size of the Page field? c) What is the size of the Offset field? d) What is the size of the Page Frame field?Consider an operating system using memory mapping on a page basis and using a single level page table. Assume that the necessary page table is always in memory. The system takes 200 ns to make a memory reference, how long does a paged memory reference take? Group of answer choices 400 ns (nanoseconds) 809.2 ms (microseconds) 200 ns (nanoseconds) 1638.4 ms (microseconds)Suppose the page table for the process currently executing on the processor looks like the following. All numbers are decimal, everything is numbered starting from zero, and all addresses are memory byte addresses. The page size is 1,024 bytes. Virtual page number 0 Valid bit Reference bit Modify bit Page frame number 1 1 0 1 1 7 2 0 0 0 3 1 0 0 2 4 0 0 0 5 1 0 1 0 What physical address, if any, would each of the following virtual addresses correspond to? (Do not try to handle any page faults, if any.) 1,052 2,221 5,499 Edit View Insert 12pt Paragraph Format Tools Table BIU Av