A very old computer had 24-bit addresses and 4KB pages. How many virtual address bits were occupied by the page number?
Q: Consider a logical address space of 16 pages of 8192 words each, mapped onto a physical memory of…
A: Logical memory has 16 pages and each of those pages has 8192 words. In order to address every one of…
Q: Consider a logical address space of 8 pages of 1024 words each, mapped into a physical memory of 32…
A: The correct answer is option d) 13 bits and 15 bits Explanation: Physical Memory = 32 frames = 2^5…
Q: Suppose you have a byte-addressable virtual address memory system with eight virtual pages of 64…
A: Answer: 1. Since it is be addressable, each page consists of 8 bits(i.e 1byte).It consists…
Q: Suppose we have a computer system with a 44-bit virtual address, page size of 64 KB. How many pages…
A: Virtual address size = 44 bits Page size = 64KB Page offset bits =log2 64KB = 16 bits So page number…
Q: Consider a paging system with the following: Physical memory= 32 bytes. Page size=4 bytes. Page…
A: Page size = 4B. So page offset = 2 bits. The offset for physical and virtual address is same. A)…
Q: Consider a system using a 2-level page table tree for address translation, with 16 KiB pages, 8 byte…
A: The virtual memory address space is defined as space or the place that is used to store by the which…
Q: Consider a logical address with a page size of 16 KB. How many bits must be used to represent the…
A: The number of bits required to store the page offset in the logical address is 14. Therefore, the…
Q: Consider a logical address space of 32 pages of 1024 words each, mapped onto a physical memory of 8…
A: Logical Address space: This address space is generated by the process running on the CPU for a…
Q: Given that the main memory size is 32KB, the page size is 64B, the word size is 1B, and n-level…
A:
Q: In a page addressing system of 15 bits, where eight bits are used for the page number, what would be…
A: The above question is solved in step 2 :-
Q: Consider a logical address space of 64 pages with 2048 words per page; mapped onto a physical memory…
A: A virtual address is known as logical address, it provide reference for CPU to access the physical…
Q: Give the number of the virtual page that the byte with virtual memory address 52000 belongs to,…
A: Page size = 8KiB This means page offset = log 8KiB = 13 bits So the least significant 13 bits will…
Q: Consider a paging system with the following: Physical memory= 32 bytes. Page size=4 bytes. Page…
A: First we see what is actual location and what is coherent location :- Consistent Address - Logical…
Q: How many bits are in a physical address?
A: There are 4 pages frames of size 64 each, or 22 x 26=28. So each physical address has 8 bits.
Q: Consider a logical address of 128 pages of 1024 words each, mapped onto a physical memory of 64…
A: Hey there, I am writing the required solution based on the above given question. Please do find the…
Q: A machine has 48-bit virtual addresses and 32-bit physical addresses. Pages are 8 KB. How many…
A: Actually, given information: A machine has 48-bit virtual addresses 32-bit physical addresses.
Q: Suppose we have a computer system with 44-bit logical addresses, page size of 64KiB, and 4 bytes per…
A: The answer is explained in detailed below:
Q: Suppose a process page table contains the entries shown below. Using the format shown in Figure…
A: The process pages are located as follows:
Q: Consider a logical address space of 256 pages with a 4-KB page size, mapped onto a physical memory…
A: The answer is as follows.
Q: An operating system on a hypothetical computer provides its users with a virtual memory space of…
A: We need to find page number refered by virtual address 12345678h.
Q: consider a computer system using paging to manage memory; suppose it has 64K (2-) bytes of memory…
A:
Q: Suppose that a machine has 38-bit virtual addresses and 32-bit physical addresses. (a) What is the…
A: Given Suppose that a machine has 38-bit virtual addresses and 32-bit physical addresses.(a) What is…
Q: Suppose that we have a computer system with a logical address space of 4,096 pages with an 2-KB page…
A: Given: Page size: 2-KB Frames: 512
Q: Consider a system with 39-bit virtual addresses, 44-bit physical addresses, 4096 byte pages, and
A: The answer is
Q: Consider a logical address space of 1024 pages with 2 KB page size, mapped onto a physical memory of…
A: The above question can be solved using formula: Size of physical…
Q: 9. Consider a system that uses 32-bit addresses and page table structures as discussed in class. If…
A: 32 bits= 2^5 256 pages= 2^8
Q: For a system employing paging, consider a logical address space of 1024 pages of 4096 bytes, mapping…
A: Here we have to find but used for logical address space(LAS)..LAS is consist of two parts page no…
Q: A computer has 64-bit virtual addresses, byte-addressed memory, 4 Kbyte page size, 4 M page frames…
A: Here as per the question given that Virtual address= 64bit Page size= 4Kbytes given as 8bits of…
Q: Consider a computer system with a 24-bit logical address and a 28-bit physical address. Let's…
A:
Q: 1. Consider a logical address of 128 pages of 1024 words each, mapped onto a physical memory of 64…
A: The answer as given below:
Q: Consider the following portion of a page table from a system with 4 KiB (i.e., 4096 byte) pages.…
A: We have given portion of page table and page size is 4KiB. Using virtual memory address, we have to…
Q: Consider a computer system with 32-bit virtual addressing and a page size of sixty-four kilobytes.…
A: In this question, we are given virtual address and physical memory size and also page size. Page…
Q: If a system has a 4-MB address space, where each page is 4 KB, and page table accesses take 100 nS,…
A: Given Data : Size of Address Space = 4 MB Size of the page = 4 KB One page tablet/page access…
Q: Consider a logical address space of 256 pages with a 4-KB page size, mapped onto a physical memory…
A: According to the Question below the Solution:
Q: Suppose the virtual address width is 32 bits. Also suppose that the virtual and physical page size…
A: We have , Virtual Address = 32-bits Virtual and Physical page size = 4KB…
Q: Suppose that we have a computer system with a 19-bit logical address and 4 KB page size. How many…
A: We are given with logical address generated by the CPU. We generate 19 bits. The page is 4KB We…
Q: Consider a logical address space of 256 pages of 1024 words each. This is mapped onto a physical…
A: Given: logical address space= of 256 pages of 1024 words each. the physical memory=32 frames. We…
Q: Consider a system that has a 20-bit virtual address, a 16-bit physical address, and a 4-KB page…
A:
Q: A computer with 32 bits virtual address uses a two-level page table. Virtual addresses are split…
A: GIVEN: A computer with 32 bits virtual address uses a two-level page table. Virtual addresses are…
Q: In a 12-bit machine with page size of 128, we have a physical address of 1000 1001 1011. What is the…
A: Given physical address=100010011011=2203 Page size=128
Q: Our system is using virtual memory and has 48-bit virtual address space and 32-bit physical address…
A: A. Page size = 8KiB So page offset bits = 13 bits Total # of page table entries required = total…
Q: Consider a logical address space of 1K pages with a 4KB page size, mapped onto a physical memory of…
A: (1) Logical address space (size)=2m then: Logical address space(size)= no of pages ×page size…
Q: Consider a logical address space of 1024 pages with 2 KB page size, mapped onto a physical memory of…
A: As given, we need to find out, how many bits are required in the logical address. Given data -…
Q: Q5) Consider a machine with 64 MB physical memory and a 32-bit virtual address space. If the page…
A: Virtual Address space is = 32 Bit Given page size = 4kb = 22 x 210 = 212 Page Table entries (PTE) =…
Q: Consider a computer system with a 32-bit logical address and 4-KB page size. The system supports up…
A: A) Number of entries in conventional single level page table = number of pages in virtual address =…
Q: Suppose we have a byte-addressable computer using a direct mapped caching with 20-bit main memory…
A: Actually, binary numbers are 1's and 0's. 1 byte =8 bits
Q: Consider a computer system with a 30-bit logical address and 4-KB page size. The system supports up…
A: (1) it is given that: logical memory space = 30 bit = 2^30 bytes given page size is 4KB = 2^12…
Q: Consider a computer system with a 30-bit logical address and 4-KB page size. The system supports up…
A: 1.
Q: Consider a logical address space of 1024 pages of 2048 words each, mapped onto a physical memory of…
A: Question :-
A very old computer had 24-bit addresses and 4KB pages. How many virtual address bits were occupied by the page number?
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- If a microprocessor has a cycle time of 0.5 nanoseconds, what’s the processor clock rate? If the fetch cycle is 40% of the processor cycle time, what memory access speed is required to implement load operations with zero wait states and load operations with two wait states?Suppose we have a computer system with a 44-bit virtual address, page size of 64 KB. How many pages are in the virtual address space?A main memory in a computer uses pages of 1024 bytes and has a page table of 64 entries. What is the length of a logical address in bits in this computer? answer a)32 b)24 c)16 d)12
- A computer with a 32-bit address uses a two-level page table. Virtual addresses are split into a 9-bit top-level page table field, an 11-bit second-level page table field, and an offset. How large are the pages and how many are there in the address space?Computer Science If a system has a 4-MB address space, where each page is 4 KB, and page table accesses take 100 nS, how long does it take to load a complete page table? What fraction of a 100 mS time slice does this take?Suppose a computer system uses 16 but addresses for both virtual and physical address. In addition, assume each page (and frame) has a size of 256 bytes. -How many bits are used for page number? -How many bits for offset? -what is the max number of pages a process can have?
- A machine has 48-bit virtual addresses and 32-bit physical addresses. Pages are 8 KB. How many entries are needed for a single-level linear page table?Given a virtual memory of size 4 GiB, physical memory of size 512 KiB, and page size equal to 4 KiB. How many bits are used to specify a physical page number?What are the steps in computing for the physical address? Give sample computations.
- What is the reachable memory space for a computer using a 12-bit address mechanism? What is the maximum amount of memory bits that this computer can have assuming memory cells are 4 bits in size?Given a virtual memory of size 4 GiB, physical memory of size 1 GiB, and page size equal to 256 KiB. How many bits are used to specify a virtual page number?Suppose that we have a computer system with a logical address space of 4,096 pages with an 8-KB page size, mapped onto a physical memory of 512 frames. How many bits are required in the logical address? *Give your answer in decimal number format.