A hydrogen atom undergoes a transition from an excited state to the ground state by emitting a photon. The energy difference between the excited state and the ground state is 2.04 eV. The wavelength of the emitted photon is measured to be 656 nm. Calculate the frequency and the energy of the emitted photon in Joules. (Note: You may use the following conversions: 1 eV = 1.6 x 10^-19 J and the speed of light, c = 3.0
A hydrogen atom undergoes a transition from an excited state to the ground state by emitting a photon. The energy difference between the excited state and the ground state is 2.04 eV. The wavelength of the emitted photon is measured to be 656 nm. Calculate the frequency and the energy of the emitted photon in Joules. (Note: You may use the following conversions: 1 eV = 1.6 x 10^-19 J and the speed of light, c = 3.0
Modern Physics
3rd Edition
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Chapter4: The Particle Nature Of Matter
Section: Chapter Questions
Problem 18P
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A hydrogen atom undergoes a transition from an excited state to the ground state by emitting a photon. The energy difference between the excited state and the ground state is 2.04 eV. The wavelength of the emitted photon is measured to be 656 nm. Calculate the frequency and the energy of the emitted photon in Joules.
(Note: You may use the following conversions: 1 eV = 1.6 x 10^-19 J and the
Give your answer to the nearest whole number.
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