A ife insurence selesmen sells on the avercye policies per week. Use Pai ssun's lqu to cal culate the probebility that n the next 1.5weeks he will Jome policies 2 or policies more policies bett less than 5 M)) assuming that there are probability that in a qiven cley he will sell on e S wiking days per week, what is the policy?

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A ife insurence selesmen sells on
the avercye
policies per week. Use Pai ssun's lqu to cal culate the probebility
that n the next 1.5weeks he will
Jome policies
2 or policies
more policies bett less than 5
M)) assuming that there are
probability that in a qiven cley he will sell on e
S wiking days per week, what is the
policy?
Transcribed Image Text:A ife insurence selesmen sells on the avercye policies per week. Use Pai ssun's lqu to cal culate the probebility that n the next 1.5weeks he will Jome policies 2 or policies more policies bett less than 5 M)) assuming that there are probability that in a qiven cley he will sell on e S wiking days per week, what is the policy?
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The number of life insurance policies sold in 1 week, on an average, is 2.

As a result, the number of life insurance policies sold in 1.5 weeks, on an average, is 3 (= 2 × 1.5).

Denote X as the number of life insurance policies sold in a randomly chosen 1.5-week period. It is given that X has a Poisson distribution.

If X ~ Poisson (λ), where λ is the average rate of occurrence of the event of interest in a specified period, where the occurrences are independent of each other, then the probability mass function of X is:

Statistics homework question answer, step 2, image 1

In this, case, it can be said that X has a Poisson distribution with parameter, λ = 3.

It is required to find the probability that the salesman sells some, say X = x policies in a particular 1.5-week period.

Hence, using the probability mass function of a Poisson distribution, the probability that the salesman sells some policies in 1.5 weeks:

Statistics homework question answer, step 2, image 2

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