0m2a)In the situation illustrated above the massm₁ is at rest initially. Show that themaximum possible value of the mass m₂for which my will not slip down the slopeis given by m = m₁ (μs cos 0 - sin 0).For a particular case, m₁ = 25 kg, 0 = 15°,Ms = 0.32 and μk = 0.16, where μk is thecoefficient of kinetic friction between themass m₁ and the slope. b)Calculate the acceleration of mass m₁parallel to the slope when m₂ = 0.63 kg.c)Calculate the acceleration of mass m₁parallel to the slope when m₂ = 2.9 kg.

Answered: Image /qna-images/answer/561bc3c2-a4a8-460c-88e4-3a64ff20a2a3.jpg

a) In the situation illustrated above the mass m₁ is at rest initially. Show that the maximum possible value of the mass m₂ for which m₁ will not slip down the slope is given by m = m₁ (μ, cos sin 0). 0 - For a particular case, m₁ = 25 kg, 0 = 15°, Ms = 0.32 and μk = 0.16, where μk is the Mk coefficient of kinetic friction between the mass m₁ and the slope.

a) In the situation illustrated above the mass m₁ is at rest initially. Show that the maximum possible value of the mass m₂ for which m₁ will not slip down the slope is given by m = m₁ (μ, cos sin 0). 0 - For a particular case, m₁ = 25 kg, 0 = 15°, Ms = 0.32 and μk = 0.16, where μk is the Mk coefficient of kinetic friction between the mass m₁ and the slope.

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter7: Dry Friction

Section: Chapter Questions

Problem 7.79P: The coefficient of rolling resistance between the 30-kg lawn roller and the ground is r=0.1. (a)...

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