A light beam is incident from air at 0₂ = 45° on the top face AB of a prism. The other two faces of the prism (AC and BC) are partially submerged into a liquid with refractive index n₁ = √3/2. The index of refraction of the prism is np = √3. The beam of light emerges from the prism parallel to the prism- liquid interface BC. Determine the prism apex angle at point B. 0a 8 = 15.0° 0 = 20.9° 9=30.0° = 45.0° C A na = 1 np = √3 0 n₁ = √3/2

A light beam is incident from air at 0₂ = 45° on the top face AB of a prism. The other two faces of the prism (AC and BC) are partially submerged into a liquid with refractive index n₁ = √3/2. The index of refraction of the prism is np = √3. The beam of light emerges from the prism parallel to the prism- liquid interface BC. Determine the prism apex angle at point B. 0a 8 = 15.0° 0 = 20.9° 9=30.0° = 45.0° C A na = 1 np = √3 0 n₁ = √3/2

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter25: Reflection And Refraction Of Light

Section: Chapter Questions

Problem 7OQ: Light traveling in a medium of index of refraction n1 is incident on another medium having an index...

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Light traveling in a medium of index of refraction n1 is incident on another medium having an index of refraction n2. Under which of the following conditions can total internal reflection occur at the interface of the two media? (a) The indices of refraction have the relation n2 n1. (b) The indices of refraction have the relation n1 n2. (c) Light travels slower in the second medium than in the first. (d) The angle of incidence is less than the critical angle. (e) The angle of incidence must equal the angle of refraction.
Figure P23.28 shows a curved surface separating a material with index of refraction n1 from a material with index n2. The surface forms an image I of object O. The ray shown in red passes through the surface along a radial line. Its angles of incidence and refraction are both zero, so its direction does not change at the surface. For the ray shown in blue, the direction changes according to n1 sin 1 = n2 sin 2. For paraxial rays, we assume 1 and 2 are small, so we may write n1 tan 1 n2 tan 2. The magnification is defined as M = h/h. Prove that the magnification is given by M = n1q/n2p. Figure P23.28
The left face of a biconvex lens has a radius of curvature of magnitude 12.0 cm, and the right face has a radius of curvature of magnitude 18.0 cm. The index of refraction of the glass is 1.44. (a) Calculate the focal length of the lens for light incident from the left. (b) What If? After the lens is turned around to interchange the radii of curvature of the two faces, calculate the focal length of the lens for light incident from the left.
Two rays travelling parallel to the principal axis strike a large plano-convex lens having a refractive index of 1.60 (Fig. P23.54). If the convex face is spherical, a ray near the edge does not pass through the local point (spherical aberration occurs). Assume this face has a radius of curvature of R = 20.0 cm and the two rays are at distances h1 = 0.500 cm and h2 = 12.0 cm from the principal axis. Find the difference x in the position where each crosses the principal axis. Figure P23.54
Two rays travelling parallel to the principal axis strike a large plano-convex lens having a refractive index of 1.60 (Fig. P23.54). If the convex face is spherical, a ray near the edge does not pass through the local point (spherical aberration occurs). Assume this face has a radius of curvature of R = 20.0 cm and the two rays are at distances h1 = 0.500 cm and h2 = 12.0 cm from the principal axis. Find the difference x in the position where each crosses the principal axis. Figure P23.54
Light enters a prism of crown glass and refracts at an angle of 5.00 with respect to the normal at the interface. The crown glass has a mean index of refraction of 1.51. It is combined with one flint glass prism (n = 1.65) to produce no net deviation. a. Find the apex angle of the flint glass. b. Assume the index of refraction for violet light (v = 430 nm) is nv = 1.528 and the index of refraction for red light (r = 768 nm) is nr = 1.511 for crown glass. For flint glass using the same wavelengths, nv = 1.665 and nr = 1.645. Find the net dispersion.
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A person looking into an empty container is able to see the far edge of the containers bottom, as shown in Figure P22.23a. The height of the container is h, and its width is d. When the container is completely filled with a fluid of index of refraction n and viewed from the same angle, the person can see the center of a coin at the middle of the containers bottom, as shown in Figure P22.23b. (a) Show that the ratio h/d is given by hd=n214n2 (b) Assuming the container has a width of 8.00 cm and is filled with water, use the expression above to find the height of the container.
Figure P23.28 shows a curved surface separating a material with index of refraction n1 from a material with index n2. The surface forms an image I of object O. The ray shown in red passes through the surface along a radial line. Its angles of incidence and refraction are both zero, so its direction does not change at the surface. For the ray shown in blue, the direction changes according to n1 sin 1 = n2 sin 2. For paraxial rays, we assume 1 and 2 are small, so we may write n1 tan 1 n2 tan 2. The magnification is defined as M = h/h. Prove that the magnification is given by M = n1q/n2p. Figure P23.28