A light beam shines through air and then strikes a mirror, making an angle theta = 58.0 degrees with respect to the vertical, as shown. The reflected beam then strikes a pane of glass of thickness h = 1.23 cm, located a distance y= 28.3 cm from the mirror, and then exits the glass pane at the bottom, a horizontal distance x cm away from where it struck the mirror. What is the value of x? 27.7 cm 46.1 cm 23.1 cm 55.3 cm
A light beam shines through air and then strikes a mirror, making an angle theta = 58.0 degrees with respect to the vertical, as shown. The reflected beam then strikes a pane of glass of thickness h = 1.23 cm, located a distance y= 28.3 cm from the mirror, and then exits the glass pane at the bottom, a horizontal distance x cm away from where it struck the mirror. What is the value of x? 27.7 cm 46.1 cm 23.1 cm 55.3 cm
Physics for Scientists and Engineers
10th Edition
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter1: Physics And Measurement
Section: Chapter Questions
Problem 26P: Review. Prove that one solution of the equation 2.00x43.00x3+5.00x=70.0 is x = 2.22.
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4. Please refer to Figure 2. A light beam shines through air and then strikes a mirror, making an angle theta = 58.0 degrees with respect to the vertical, as shown. The reflected beam then strikes a pane of glass of thickness h = 1.23 cm, located a distance y= 28.3 cm from the mirror, and then exits the glass pane at the bottom, a horizontal distance x cm away from where it struck the mirror. What is the value of x?
27.7 cm
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46.1 cm
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23.1 cm
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55.3 cm
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