A local juice manufacturer distributes juice in bottles labeled 32 ounces. A government agency thinks that the company is cheating its customers. The agency selects 35 of these bottles, measures their contents, and obtains a sample mean of 31.7 ounces with a standard deviation of 0.70 ounce. Use a 5% significance level to test the agency's claim that the company is cheating its customers. The appropriate null hypothesis for this situation is: H0: = 31.7H0: μ = 32 H0: = 32H0: μ = 31.7 The appropriate alternative hypothesis for this situation is: Ha: < 32Ha: > 31.7 Ha: < 31.7Ha: > 32Ha: μ > 32Ha: μ < 31.7Ha: μ > 31.7Ha: μ < 32 The value of the statistic for this test is = (round answers to three places after the decimal.) and the p-value is (round answers to three places after the decimal.) There enough statistical evidence, at the 5% level, that the company is cheating its customers.
A local juice manufacturer distributes juice in bottles labeled 32 ounces. A government agency thinks that the company is cheating its customers. The agency selects 35 of these bottles, measures their contents, and obtains a sample mean of 31.7 ounces with a standard deviation of 0.70 ounce. Use a 5% significance level to test the agency's claim that the company is cheating its customers.
The appropriate null hypothesis for this situation is:
The appropriate alternative hypothesis for this situation is:
The value of the statistic for this test is = (round answers to three places after the decimal.)
and the p-value is (round answers to three places after the decimal.)
There enough statistical evidence, at the 5% level, that the company is cheating its customers.
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