A long jumper (above Fig.) leaves the ground at an angle of 20° to the horizontal and at a speed of 11 m/s. (a) How long does it take for him to reach maximum height? t (b) What is the maximum height? yma= (c) How far does he jump? R= (d) Use Equation v = vy - 2gAy to find the maximum height he reaches. y

Principles of Physics: A Calculus-Based Text
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Chapter3: Motion In Two Dimensions
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[ Q2-b Qx %&f’i“& A long jumper (above Fig.) leaves the ground at an angle of 20 1o the horizontal and at aspeed of 11 mis. (a) How long does it take for (b) What s the maximum height (©) How far does he jump? R- (@) Use Equation v = v, ~ 2Ay to find the maimum heigh he reaches. Yo~ o reach i height? (. — Sl
نقطتان )2(
Q2-b
Q2:
A long jumper (above Fig.) leaves the ground at an angle of 20° to the horizontal and at
a speed of 11 m's.
(a) How long does it take for him to reach maximum height? t
(b) What is the maximum height? ymax
(c) How far does he jump? R=
(d) Use Equation v? = vy – 2gAy to find the maximum height he reaches. yma
Transcribed Image Text:نقطتان )2( Q2-b Q2: A long jumper (above Fig.) leaves the ground at an angle of 20° to the horizontal and at a speed of 11 m's. (a) How long does it take for him to reach maximum height? t (b) What is the maximum height? ymax (c) How far does he jump? R= (d) Use Equation v? = vy – 2gAy to find the maximum height he reaches. yma
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