A long straight conductor PQ, carrying a current of 60 A, is fixed horizontally. Another long conductor XY is kept parallel to PQ at a distance of 4 mm, in air. Conductor XY is free to move and carries a current I. Calculate the magnitude and direction of current I for which the magnetic repulsion just balances the weight of conductor XY. (Mass per P. FIGURE 3(b).23 X Y 4mm unit lengths for conductor XY is 10-2 kg/m). I, = 60A

University Physics Volume 2
18th Edition
ISBN:9781938168161
Author:OpenStax
Publisher:OpenStax
Chapter12: Sources Of Magnetic Fields
Section: Chapter Questions
Problem 25P: A long, straight, horizontal wire carries a left-to-right current of 20 A. If the wire is placed in...
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A long straight conductor PQ, carrying a
current of 60 A, is fixed horizontally. Another long conductor
XY is kept parallel to PQ at a distance of 4 mm, in air. Conductor
XY is free to move and carries a current I. Calculate the
magnitude and direction of current I for which the magnetic
repulsion just balances the weight of conductor XY. (Mass per
P.
FIGURE 3(b).23
X
4mm
unit lengths for conductor XY is 10-2 kg/m).
I = 60A
Transcribed Image Text:A long straight conductor PQ, carrying a current of 60 A, is fixed horizontally. Another long conductor XY is kept parallel to PQ at a distance of 4 mm, in air. Conductor XY is free to move and carries a current I. Calculate the magnitude and direction of current I for which the magnetic repulsion just balances the weight of conductor XY. (Mass per P. FIGURE 3(b).23 X 4mm unit lengths for conductor XY is 10-2 kg/m). I = 60A
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