A man is running around a circular track that is 200 m in circumference. An observer uses a stopwatch to record the runner's time at the end of each lap, obtaining the data in the following table. Time (s) Distance (m) 42 200 90 400 139 600 202 800 266 1000 336 1200 413 1400 492 1600 (a) What was the man's average speed (rate) between 90 s and 202 s? (Round your answer to two decimal places.) m/s

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A: We can solve this using least square method

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Q: A car on a test rack accelerates from 0 ft/s to 132 ft/s in 8 seconds. The car's velocity at time t…

A: Acceleration  is defined as rate of change of velocity. Hence, acceleration, a = dv/dt = Δv/Δt

Q: When estimating distances from a table of velocity data, it is not necessary that the time intervals…

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Q: We have data on the lean body mass and resting metabolic rate for 12 women who are subjects in a…

A: Note: Hey there! Thank you for the question. As you have posted several sub-parts of a question,…

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Q: The manager of a bank decide to compare the speed on the job of four tellers working in the bank.…

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Q: Each person in random samples of 207 male and 263 female working adults living in a certain town in…

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Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.