A man is standing on the edge of a 20.0 mhigh cliff. He throws a rock vertically with aninitial velocity of 10.0 m/s.a)5.How high does the rock go?(Remember that at its max height v = 0m/s)How long does it take to reach its maxheight |b)

Given height of the cliff, h =20.0 m initial speed of the rock, u = 10.0 ms vertically upward

A man is standing on the edge of a 20.0 m high cliff. He throws a rock vertically with an initial velocity of 10.0 m/s. a) How high does the rock go? (Remember that at its max height v = 0 m/s) b) How long does it take to reach its max height

A man is standing on the edge of a 20.0 m high cliff. He throws a rock vertically with an initial velocity of 10.0 m/s. a) How high does the rock go? (Remember that at its max height v = 0 m/s) b) How long does it take to reach its max height

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter2: Motion In One Dimension

Section: Chapter Questions

Problem 2.55P: A daring ranch hand sitting on a tree limb wishes to drop vertically onto a horse galloping under...

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Concept explainers

Relative Velocity

It is a measurement of an object with regards to the other object which is moving or stable or stationary. For example, if we are traveling in a bus and the bus is moving at speed of 50km/hr, then our speed is according to the nearby passenger on the bus is zero. According to them, we are not moving. But if one person standing on the ground or road observes us from outside of the bus, according to him we are moving at a speed of 50km/hr and the bus is also moving at a speed of 50km/hr. Now, the motion is recognized by the observer, it depends on a frame of reference or observer. This is motion called relative motion.

Question

A man is standing on the edge of a 20.0 m
high cliff. He throws a rock vertically with an
initial velocity of 10.0 m/s.
a)
5.
How high does the rock go?
(Remember that at its max height v = 0
m/s)
How long does it take to reach its max
height |
b)

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