A man with a mass of 72.1 kg stands on one foot. His femur has a cross-sectional area of 8.00 cm2 and an uncompressed length 49.6 cm. Young’s modulus for compression of the human femur is 9.40 × 109 N/m2.a.How much shorter is the femur when the man stands on one foot?b.What is the fractional length change of the femur when the person moves from standing on two feet to standing on one foot?

Given, M=72.1 kgg=9.81 m/s2W=Mg=72.1×9.81=707.301 NA=8.00 cm2=8×10-4 m2L=49.6 cm=0.496 mE=9.40×109…

Answered: A man with a mass of 72.1 kg stands on…

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter14: Static Equilibrium, Elasticity, And Fracture

Section: Chapter Questions

Problem 66PQ: A steel cable 2.00 m in length and with cross-sectional radius 0.350 mm is used to suspend from the...

See similar textbooks

Related questions

Concept explainers

Question

A man with a mass of 72.1 kg stands on one foot. His femur has a cross-sectional area of 8.00 cm² and an uncompressed length 49.6 cm. Young’s modulus for compression of the human femur is 9.40 × 10⁹ N/m².

a.How much shorter is the femur when the man stands on one foot?

b.What is the fractional length change of the femur when the person moves from standing on two feet to standing on one foot?

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions