A manufacturer of Li-based batteries claims that their newly designed batteries will last, on average, 6 years with a standard deviation of 1 year. A random sample of 9 of these batteries was tested and found to have the following expected lifetimes in years: 4.0 7.0 6.8 7.9 6.0 6.5 5.0 5.2 5.7 To decide if the manufacturer's claim is valid on the mean or variance of the battery, you were asked to provide an analysis and interpretation. Assume the population of battery lives to be approximately normally distributed.
A manufacturer of Li-based batteries claims that their newly designed batteries will last, on average, 6 years with a standard deviation of 1 year. A random sample of 9 of these batteries was tested and found to have the following expected lifetimes in years: 4.0 7.0 6.8 7.9 6.0 6.5 5.0 5.2 5.7 To decide if the manufacturer's claim is valid on the mean or variance of the battery, you were asked to provide an analysis and interpretation. Assume the population of battery lives to be approximately normally distributed.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
1a
![What is the computed sample mean (expressed in 2 significant figures or
1 decimal place) ? 6
years
nstructure.com/courses/77529/quizzes/197919
PM
Long Quiz #2 (Problem Solving): [1211 DATAENG_EH] - ENGINEERING DATA ANALYSIS
What is the computed sample standard deviation (expressed in 2
significant figures or 1 decimal place) ? 1.2
years
Given the 95% confidence interval around the mean where the average
battery lifetime will lie in between 5.1
years and
6.9
years (expressed the lower bound and upper bound
in two significant figures), the manufacturer's claim about the average
lifetime is valid
(write "valid" or "not valid") at
95
% significance level.
To decide whether the manufacturer's claim that the variability in terms of
variance or standard deviation is 1, the standard deviation at 95 %
confidence interval is in between 0.7
and
5.3
years (expressed the lower bound and upper bound
in two significant figures).
Thus, the manufacturer's claim about the variance is valid
(write "valid" or "not valid") at 95
% significance level.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb2e41a6d-af86-4099-830d-f3243855c9a0%2F0d1d24f1-bba3-4af0-a5df-bc6b9a007ddd%2Fampyfn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:What is the computed sample mean (expressed in 2 significant figures or
1 decimal place) ? 6
years
nstructure.com/courses/77529/quizzes/197919
PM
Long Quiz #2 (Problem Solving): [1211 DATAENG_EH] - ENGINEERING DATA ANALYSIS
What is the computed sample standard deviation (expressed in 2
significant figures or 1 decimal place) ? 1.2
years
Given the 95% confidence interval around the mean where the average
battery lifetime will lie in between 5.1
years and
6.9
years (expressed the lower bound and upper bound
in two significant figures), the manufacturer's claim about the average
lifetime is valid
(write "valid" or "not valid") at
95
% significance level.
To decide whether the manufacturer's claim that the variability in terms of
variance or standard deviation is 1, the standard deviation at 95 %
confidence interval is in between 0.7
and
5.3
years (expressed the lower bound and upper bound
in two significant figures).
Thus, the manufacturer's claim about the variance is valid
(write "valid" or "not valid") at 95
% significance level.
Transcribed Image Text:A manufacturer of Li-based batteries claims that their newly designed
batteries will last, on average, 6 years with a standard deviation of 1 year.
A random sample of 9 of these batteries was tested and found to have the
following expected lifetimes in years:
4.0
7.0
6.8
7.9
6.0
6.5
5.0
5.2
5.7
To decide if the manufacturer's claim is valid on the mean or variance of
the battery, you were asked to provide an analysis and interpretation.
Assume the population of battery lives to be approximately normally
distributed.
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