A market research firm used a sample of individuals to rate the purchase potential of a particular product before and after the individuals saw a new television commercial about the product. The purchase potential ratings were based on a 0 to 10 scale, with higher values indicating a higher purchase potential. The null hypothesis stated that the mean rating "after" would be less than or equal to the mean rating "before." Rejection of this hypothesis would show that the commercial improved the mean purchase potential rating. Use a = 0.05 and the following data to test the hypothesis and comment on the value of the commercial. Purchase Rating Individual After Before 5 2 6 4 5 3 6. 6. 9 8. 7 8. 6 7 State the null and alternative hypotheses. (Use H = mean rating after - mean rating before.) O Ho: HosO Hgi Hg = 0 O Ho: HosO Hai Hq> 0 O Ho: Ho *0 Hoi Ho = 0 O Ho: Ho = 0 O Ho: Hg>0 Calculate the value of the test statistic. (Round your answer to three decimal places.)

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Chapter4: Equations Of Linear Functions
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Calculate the p-value. (Round your answer to four decimal places.)
p-value =
State your conclusion.
Reject Ho. There is sufficient evidence to conclude that seeing the commercial improves the mean potential to purchase.
Reject Ho. There is insufficient evidence to conclude that seeing the commercial improves the mean potential to purchase.
Do not Reject Ho. There is sufficient evidence to conclude that seeing the commercial improves the mean potential to purchase.
Do not reject Ho: There is insufficient evidence to conclude that seeing the commercial improves the mean potential to purchase.
Transcribed Image Text:Calculate the p-value. (Round your answer to four decimal places.) p-value = State your conclusion. Reject Ho. There is sufficient evidence to conclude that seeing the commercial improves the mean potential to purchase. Reject Ho. There is insufficient evidence to conclude that seeing the commercial improves the mean potential to purchase. Do not Reject Ho. There is sufficient evidence to conclude that seeing the commercial improves the mean potential to purchase. Do not reject Ho: There is insufficient evidence to conclude that seeing the commercial improves the mean potential to purchase.
A market research firm used a sample of individuals to rate the purchase potential of a particular product before and after the individuals saw a new television commercial about the product. The
purchase potential ratings were based on a 0 to 10 scale, with higher values indicating a higher purchase potential. The null hypothesis stated that the mean rating "after" would be less than or equal to
the mean rating "before." Rejection of this hypothesis would show that the commercial improved the mean purchase potential rating. Use a = 0.05 and the following data to test the hypothesis and
comment on the value of the commercial.
Purchase Rating
Individual
After
Before
1
6
2
6
7
7
4
4
3
6.
6.
9.
7
7
6.
7
State the null and alternative hypotheses. (Use ud
= mean rating after
mean rating before.)
Ha: Hd
0 5 Pr :0H
= 0
Ho: Ha s 0
Hai Hd>
O Ho: Ha# 0
Hai Hd = 0
%D
Ho: Hd = 0
Ha: Ha# 0
O Ho: Ha> 0
Calculate the value of the test statistic. (Round your answer to three decimal places.)
Transcribed Image Text:A market research firm used a sample of individuals to rate the purchase potential of a particular product before and after the individuals saw a new television commercial about the product. The purchase potential ratings were based on a 0 to 10 scale, with higher values indicating a higher purchase potential. The null hypothesis stated that the mean rating "after" would be less than or equal to the mean rating "before." Rejection of this hypothesis would show that the commercial improved the mean purchase potential rating. Use a = 0.05 and the following data to test the hypothesis and comment on the value of the commercial. Purchase Rating Individual After Before 1 6 2 6 7 7 4 4 3 6. 6. 9. 7 7 6. 7 State the null and alternative hypotheses. (Use ud = mean rating after mean rating before.) Ha: Hd 0 5 Pr :0H = 0 Ho: Ha s 0 Hai Hd> O Ho: Ha# 0 Hai Hd = 0 %D Ho: Hd = 0 Ha: Ha# 0 O Ho: Ha> 0 Calculate the value of the test statistic. (Round your answer to three decimal places.)
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