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A marketing consultant is hired by a major restaurant chain wishing to investigate the preferences and spending patterns of lunch customers. The CEO of the chain hypothesized that the average customer spends at least $13.50 on lunch. A survey of 25 customers sampled at one of the restaurants found the average lunch bill per customer to be $15.50. Based on previous surveys, the restaurant informs the marketing manager that the standard deviation is a $3.50. To address the CEO's conjecture, the marketing manager carried out a hypothesis test of μ = 13.50 vs.: u 13.50 and obtained a P-value = 0.002. At a significance level of a = 0.05, this result: a. proves without a doubt that the average lunch bill exceeds $13.50. O b. proves without a doubt that the average lunch bill does not exceed $13.50. O c. provides evidence against the null hypothesis hypothesis in favor of the alternative. hypothesis. O d. does not provide evidence against the null hypothesis in favor of the alternative hypothesis.

A marketing consultant is hired by a major restaurant chain wishing to investigate the preferences and spending patterns of lunch customers. The CEO of the chain hypothesized that the average customer spends at least $13.50 on lunch. A survey of 25 customers sampled at one of the restaurants found the average lunch bill per customer to be $15.50. Based on previous surveys, the restaurant informs the marketing manager that the standard deviation is a $3.50. To address the CEO's conjecture, the marketing manager carried out a hypothesis test of μ = 13.50 vs.: u 13.50 and obtained a P-value = 0.002. At a significance level of a = 0.05, this result: a. proves without a doubt that the average lunch bill exceeds $13.50. O b. proves without a doubt that the average lunch bill does not exceed $13.50. O c. provides evidence against the null hypothesis hypothesis in favor of the alternative. hypothesis. O d. does not provide evidence against the null hypothesis in favor of the alternative hypothesis.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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A marketing consultant is hired by a major restaurant chain wishing to investigate the preferences and spending patterns of lunch customers. The CEO of the chain hypothesized that the average customer spends at least $13.50 on lunch. A survey of 25 customers sampled at one of the restaurants found the average lunch bill per customer to be $15.50. Based on previous surveys, the restaurant informs the marketing manager that the standard deviation is a = $3.50. To address the CEO's conjecture, the marketing manager carried out a hypothesis test of: μ = 13.50 vs.: μ> 13.50 and obtained a P-value = 0.002. At a significance level of a = 0.05, this result: a, proves without a doubt that the average lunch bill exceeds $13.50. O b. proves without a doubt that the average lunch bill does not exceed $13.50. O c. provides evidence against the null hypothesis hypothesis in favor of the alternative hypothesis. O d. does not provide evidence against the null hypothesis in favor of the alternative hypothesis.
Transcribed Image Text:A marketing consultant is hired by a major restaurant chain wishing to investigate the preferences and spending patterns of lunch customers. The CEO of the chain hypothesized that the average customer spends at least $13.50 on lunch. A survey of 25 customers sampled at one of the restaurants found the average lunch bill per customer to be $15.50. Based on previous surveys, the restaurant informs the marketing manager that the standard deviation is a = $3.50. To address the CEO's conjecture, the marketing manager carried out a hypothesis test of: μ = 13.50 vs.: μ> 13.50 and obtained a P-value = 0.002. At a significance level of a = 0.05, this result: a, proves without a doubt that the average lunch bill exceeds $13.50. O b. proves without a doubt that the average lunch bill does not exceed $13.50. O c. provides evidence against the null hypothesis hypothesis in favor of the alternative hypothesis. O d. does not provide evidence against the null hypothesis in favor of the alternative hypothesis.
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