A married couple decides to have a party. The husband has 8 friends and the wife has 9 friends. Unfortunately, none of the husband’s friends will attend a party that is attended by any of his wife’s friends. How many different parties of size 4 can the couple have?
A married couple decides to have a party. The husband has 8 friends and the wife has 9 friends. Unfortunately, none of the husband’s friends will attend a party that is attended by any of his wife’s friends. How many different parties of size 4 can the couple have?
Chapter9: Sequences, Probability And Counting Theory
Section: Chapter Questions
Problem 36RE: In a group of 5 freshman, 10 sophomores, 3 juniors, and 2 seniors, how many ways can a president,...
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A married couple decides to have a party. The husband has 8 friends and the wife has 9 friends. Unfortunately, none of the husband’s friends will attend a party that is attended by any of his wife’s friends. How many different parties of size 4 can the couple have?
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I was given this as the correct answer instead:
C(8,4) + C(9,4). Or 70+126= 196
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