A merry-go-round is a playground ride that consists of a large disk mounted to that it can freely rotate in a horizontal plane. The merry-go-round shown is initially at rest, has a radius R = 1.1 meters, and a mass M = 201 kg. A small boy of mass m = 43 kg runs tangentially to the merry-go-round at a speed of v = 2.5 m/s, and jumps on.Immediately before the boy jumps on the merry go round, calculate his angular speed (in radians/second) about the central axis of the merry-go-round. Immediately after the boy jumps on the merry go round, calculate the angular speed in radians/second of the merry-go-round and boy. The boy then crawls towards the center of the merry-go-round along a radius. What is the angular speed in radians/second of the merry-go-round when the boy is half way between the edge and the center of the merry go round?

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Asked Feb 2, 2020
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 A merry-go-round is a playground ride that consists of a large disk mounted to that it can freely rotate in a horizontal plane. The merry-go-round shown is initially at rest, has a radius R = 1.1 meters, and a mass M = 201 kg. A small boy of mass m = 43 kg runs tangentially to the merry-go-round at a speed of v = 2.5 m/s, and jumps on.

Immediately before the boy jumps on the merry go round, calculate his angular speed (in radians/second) about the central axis of the merry-go-round. 

Immediately after the boy jumps on the merry go round, calculate the angular speed in radians/second of the merry-go-round and boy. 

The boy then crawls towards the center of the merry-go-round along a radius. What is the angular speed in radians/second of the merry-go-round when the boy is half way between the edge and the center of the merry go round? 

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Expert Answer

Step 1

Given:

Mass of merry go round (M) = 201 kg

Mass of small boy (m) = 43 kg

Radius of merry go round (R) = 1.1 kg

Velocity of boy (v) = 2.5 m/s

Step 2

Part a)

Angular speed of boy with respect to center of merry-go-round is,

Physics homework question answer, step 2, image 1
fullscreen
Step 3

Part b)

The momentum will be conserved before and after jump. So to calculate the angular speed the angul...

Physics homework question answer, step 3, image 1
fullscreen

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Angular Motion

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