A message has been encoded by assigning the numbers 1 to 26 to the letters a to z of the alphabet, respectively, and assigning 27 to a blank space. A message of this type can be decoded by finding the inverse of the encoding matrix and multiplying it times the coded message Use A¹ and the conversion table below to decode the following message The encoding matrix is A = The decoded message is abcdefghijklmnopq stuvwxyz blank 123456789 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 12-1 2 1-3 and the encoded message is 29.-1, 75.-19. -66, 50, 46, 41, 47,3 -38,65 -14 2 0 *****

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter4: Eigenvalues And Eigenvectors
Section4.4: Similarity And Diagonalization
Problem 39EQ
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A message has been encoded by assigning the numbers 1 to 26 to the letters a to z of the alphabet, respectively, and assigning 27 to a blank
space. A message of this type can be decoded by finding the inverse of the encoding matrix and multiplying it times the coded message. Use
A and the conversion table below to decode the following message
The encoding matrix is A =
The decoded message is
abcdefghijklmnopqrstuvwxyz blank
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27
12-1
21-3 and the encoded message is 29. -1, 75.-19.-66, 50, 46, 41, 47, 3, -38,65
-14 2
Transcribed Image Text:A message has been encoded by assigning the numbers 1 to 26 to the letters a to z of the alphabet, respectively, and assigning 27 to a blank space. A message of this type can be decoded by finding the inverse of the encoding matrix and multiplying it times the coded message. Use A and the conversion table below to decode the following message The encoding matrix is A = The decoded message is abcdefghijklmnopqrstuvwxyz blank 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 12-1 21-3 and the encoded message is 29. -1, 75.-19.-66, 50, 46, 41, 47, 3, -38,65 -14 2
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