A) N2 + H2→__ NH3 5-- --- B) KCIO3 → KCI + 02 51- - C) NaCl + F2→ NaF + Cl2 D) C3H18 + CO2 + H20 --- --- ---- - ------ E) FeCl3 + NaOH > Fe(OH)3 + _NaCI F) P + _O2→ P205 G) Na + H20 → NaOH + _H2 --- ---- H) H2SO4 + Ba(NO3)2 → HNO3 + BaSO4 --- - How many decomposition reactions are there in the set of reactions above? 0 4 O 2 More than 4

A) N2 + H2→__ NH3 5-- --- B) KCIO3 → KCI + 02 51- - C) NaCl + F2→ NaF + Cl2 D) C3H18 + CO2 + H20 --- --- ---- - ------ E) FeCl3 + NaOH > Fe(OH)3 + _NaCI F) P + _O2→ P205 G) Na + H20 → NaOH + _H2 --- ---- H) H2SO4 + Ba(NO3)2 → HNO3 + BaSO4 --- - How many decomposition reactions are there in the set of reactions above? 0 4 O 2 More than 4

World of Chemistry, 3rd edition

3rd Edition

ISBN:9781133109655

Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste

Chapter17: Equilibrium

Section: Chapter Questions

Problem 12A

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Amoxicillin is an antibiotic packaged as a powder. When it is used to treat babies and small animals, the pharmacist or veterinarian must suspend it in water, so that it can be administered orally with a medicine dropper. The label says to dispose of unused suspension after 14 days. It also points out that refrigeration is required. In the context of this chapter, what is implied in the latter two statements?
Carbon ΔHof (kJ/mol) ΔGof (kJ/mol) So (J/mol K) C (s, graphite) 0 0 5.7 C (s, diamond) 1.9 2.9 2.4 C (g) 716.7 671.3 158.1 CCl4 (l) -135.4 -65.2 216.4 CCl4 (g) -102.9 -60.6 309.9 CHCl3 (l) -134.5 -73.7 201.7 CHCl3 (g) -103.1 -70.3 295.7 CH4 (g) -74.8 -50.7 186.3 CH3OH (g) -200.7 -162.0 239.8 CH3OH (l) -238.7 -166.3 126.8 H2CO (g) -116.0 -110.0 219.0 HCOOH (g) -363.0 -351.0 249.0 HCN (g) 135.1 125.0 202.0 C2H2 (g) 226.7 209.2 200.9 C2H4 (g) 52.3 68.2 219.6 Hydrogen ΔHof (kJ/mol) ΔGof (kJ/mol) So (J/mol K) H2 (g) 0 0 130.7 H (g) 218.0 203.2 114.7 H+ (g) 1536.2 H+ (aq) 0 OH- (aq) -230.0 -157.0 -11.0 H2O (l) -285.8 -237.1 69.9 H2O (g) -241.8 -228.6 188.8 H2O2 (l) -187.8 -120.4 109.6
Carbon ΔHof (kJ/mol) ΔGof (kJ/mol) So (J/mol K) C (s, graphite) 0 0 5.7 C (s, diamond) 1.9 2.9 2.4 C (g) 716.7 671.3 158.1 CCl4 (l) -135.4 -65.2 216.4 CCl4 (g) -102.9 -60.6 309.9 CHCl3 (l) -134.5 -73.7 201.7 CHCl3 (g) -103.1 -70.3 295.7 CH4 (g) -74.8 -50.7 186.3 CH3OH (g) -200.7 -162.0 239.8 CH3OH (l) -238.7 -166.3 126.8 H2CO (g) -116.0 -110.0 219.0 HCOOH (g) -363.0 -351.0 249.0 HCN (g) 135.1 125.0 202.0 C2H2 (g) 226.7 209.2 200.9 C2H4 (g) 52.3 68.2 219.6 CH3CHO (g, acetaldehyde) -166.0 -129.0 250.0 C2H4O (g, ethylene oxide) -53.0 -13.0 242.0 CH3CH2OH (l) -277.7 -174.8 160.7 CH3CH2OH (g) -235.1 -168.5 282.7 CH3COOH (l) -484.0 -389.0 160.0 C2H6 (g) -84.7 -32.8 229.6 C3H6 (g) 20.9 62.7 266.9 C3H8 (g) -103.8 -23.5 269.9 CH2=CHCN (l) 152.0 190.0 274.0…
For the reaction H2O(g) + Cl2O(g) + 2HClO(g), you know ΔSorxn and ΔSosys and So ofHClO(g) and of H2O(g). Write an expression that can be used to determine Cl2O(g).
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Which of the following is not a way to stress a chemical system? A. Pressure B. Temperature C. Addition/subtraction of a reactant or product D. Time
For certain chemical reaction ∆H = 15 kJ/mol and ∆S = 51 J mol-1 K-1, What is ∆G (in kJ/mol) for the reaction when T = a 0o ? A) 1.07 B) -1007 C) 0.107 D) 1007 E) -1.07
Determine ΔHo for the reactionN2H4 (l) + 2H2O2 (l) → N2 (g) + 4H2O (l) from: N2H4 (l) + O2 (g) → N2 (g) + 2H2O (l) - ΔHo = −622.2 kJ/mol H2 (g) + 1⁄2O2 (g) → H2O (l) - ΔHo = −285.8 kJ/mol H2 (g) + O2 (g) → H2O2 (l) - ΔHo = −187.8 kJ/mol
Consider the generic reaction:A + 2 B -------> C + 3 D ∆H = 155 kJDetermine the value of ∆H for related reaction: 3 A + 6 B --------->3 C + 9 D
Use ΔHf0 listed below to calculate ΔH0rxn for the reaction C + 4 HNO3 ----> CO2 + 4 NO2 + 2 H2O ΔHf0 (kJ/mol) 0 -174.1 -393.5 33.2 -285.8 a) -123.9 kJ b) -472.1 kJ c) -201.9 kJ d) -404.8 kJ e) -135.9 kJ
What characteristics of a chemical reaction make it reversible or irreversible?
ΔS is positive for the reaction ________. A) 2H2 (g) + O2 (g) → 2H2O (g)B) 2NO2 (g) → N2O4 (g)C) CO2 (g) → CO2 (s)D) BaF2 (s) → Ba2+ (aq) + 2F- (aq)E) 2Hg (l) + O2 (g) → 2HgO (s)