A new type of force was discovered by physicists with the following expression: Fnew + Be* + 3x4 where alpha & beta are constants, and x is the position. The expression above was obtained from the int massless Higgs Boson (a type of particle) and a black hole. Quantum physicists then decides to design and build a machine that is able to move the Higgs Boson fror How much work should the machine do to achieve this feat? (For simplicity, consider that no energy is los process) Solution To determine the work done we apply the following W- dx

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Chapter33: Particle Physics
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Problem 15PE: The mass of a theoretical particle that may be associated with the uni?cation of the electroweak and...
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A new type of force was discovered by physicists with the following expression:
Fnew
- + Bex + 3x
where alpha & beta are constants, and x is the position. The expression above was obtained from the interaction of a
massless Higgs Boson (a type of particle) and a black hole.
Quantum physicists then decides to design and build a machine that is able to move the Higgs Boson from x2 to x1.
How much work should the machine do to achieve this feat? (For simplicity, consider that no energy is lost in the
process)
Solution
To determine the work done we apply the following
W =
dx
Evaluating the above, we get
W =
e
for the limits from x¡ to
Xf
substituting x1 and x2 as the limits, the work done is expressed as
W =
| + B
X1
( x15 -
x2 )
Transcribed Image Text:A new type of force was discovered by physicists with the following expression: Fnew - + Bex + 3x where alpha & beta are constants, and x is the position. The expression above was obtained from the interaction of a massless Higgs Boson (a type of particle) and a black hole. Quantum physicists then decides to design and build a machine that is able to move the Higgs Boson from x2 to x1. How much work should the machine do to achieve this feat? (For simplicity, consider that no energy is lost in the process) Solution To determine the work done we apply the following W = dx Evaluating the above, we get W = e for the limits from x¡ to Xf substituting x1 and x2 as the limits, the work done is expressed as W = | + B X1 ( x15 - x2 )
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