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- The treatment of isoprene [CH2=C(CH3)CH=CH2] with one equivalent ofmCPBA forms A as the major product. A gives a molecular ion at 84 in itsmass spectrum, and peaks at 2850–3150 cm−1 in its IR spectrum. The 1HNMR spectrum of A is given below. What is the structure of A?The treatment of isoprene [CH2 = C(CH3)CH = CH2] with one equivalent of mCPBA forms A as the major product. A gives a molecular ion at 84 in its mass spectrum, and peaks at 2850–3150 cm−1 in its IR spectrum. The 1H NMR spectrum of A is given below. What is the structure of A?Thank you for the answer, would it be possible to follow the path I have attached as well srarting from methanol ---> CH3Br -----> CH3MgBr-------> (H3C)CH-CH2OH ----> E1 Isobutalene
- Synthesize (Z)-hept-5-en-2-one from ethyl acetoacetate (CH3COCH2CO2Et) and the given starting material. You may also use any other organic compounds or required inorganic reagents.The Favorskiireaction involves treatment of an a-bromo ketone with base to yield a ring-contracted product. For example, reaction of 2-bromocyclohexanone with aqueous NaOH yields cyclopentanecarboxylic acid.what is the mechanism of the reaction.Oxidation of cholesterol converts the alcohol to a ketone. Under acidic or basic oxidationconditions, the C“C double bond migrates to the more stable, conjugated position. BeforeIR and NMR spectroscopy, chemists watched the UV spectrum of the reaction mixture tofollow the oxidation. Describe how the UV spectrum of the conjugated product, cholest-4-en-3-one, differs from that of cholesterol
- Reaction of p-cresol with two equivalents of 2-methylprop-1-ene affordsBHT, a preservative with molecular formula C15H24O. BHT gives thefollowing 1H NMR spectral data: 1.4 (singlet, 18 H), 2.27 (singlet, 3 H), 5.0(singlet, 1 H), and 7.0 (singlet, 2 H) ppm. What is the structure of BHT?Draw a stepwise mechanism illustrating how it is formed.redraw the following reaction mechanism with benzene instead of isoborneol. it's an oxidation mechanism from OH to ketone. please include the arrow pushing.Draw the products formed when p-methylaniline (p-CH3C6H4NH2) is treated with each reagent.a. HClb. CH3COClc. (CH3CO)2Od. excess CH3Ie. (CH3)2C = Of. CH3COCl, AlCl3g. CH3CO2Hh. NaNO2, HCli. Part (b), then CH3COCl, AlCl3j. CH3CHO, NaBH3CN
- a) Write out the first 3 steps only(to the tetrahedral intermediate shown) in the 6-step arrow pushing mechanism showing how ethyl propanoate is hydrolyzed in acid to form propanoic acidand ethanol. b) NaOH/H2O also serveto hydrolyze an ester; briefly explain why NaOH/H2Ois generally preferable.select the most appropriate reagent(s) to effect the change. K2Cr2O7, H+ H2, Pd 1. Disiamylborane, 2. HO–, H2O, H2O2 NaOCl H2SO4, HgSO4Provide the mechansim using curved arrows of the reaction of p-t-butyl phenol treated with acetic anhydride in AlCl3. Include resonance stabilized intermediates and if more than one product is formed, label them as major, minor, etc. thank you for the help