A package of mass m is released from rest at a warehouse loading dock and slides down the 5.5-m-high, frictionless chute to a waiting truck. Unfortunately, the truck driver went on a break without having removed the previous package, of mass 2m, from the bottom of the chute. (Figure 1) < 1 of 1 > Figure (vo)=0 yo Part B 7=0 Before (1)2m Om (V2)3m After 2=0 0 SOLVE: For a package with mass m the conservation of energy equation is K₁+U₁₁ = Ko+Um(vi)+mgy₁ =m(vo)+mgyo Using (vo)m 0 m/s and y₁ = m(v) mgyo 0 m. (vi)m =√29yo =√2(9.8 m/s²)(5.5 m) = 10.4 m/s For the perfectly inelastic collision the conservation of momentum equation is Piz Piz (m+2m)(v2)3mm(v1)m +(2m)(v1)2m Using (1)2m 0 m/s, we get (v2)3m = (v1)m 2m+m (v1) 10.4 m/s 3 3 3.5 m/s Suppose the collision between the packages is perfectly elastic. To what height does the package of mass m rebound? Express your answer with the appropriate units. ▸ View Available Hint(s) h= 2 HA ? Units Value

College Physics
10th Edition
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter5: Energy
Section: Chapter Questions
Problem 92AP: Two blocks, A and B (with mass 50.0 kg and 1.00 102 kg, respectively), are connected by a string,...
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A package of mass m is released from rest at a warehouse loading dock
and slides down the 5.5-m-high, frictionless chute to a waiting truck.
Unfortunately, the truck driver went on a break without having removed the
previous package, of mass 2m, from the bottom of the chute. (Figure 1)
< 1 of 1 >
Figure
(vo)=0
yo
Part B
7=0
Before
(1)2m
Om
(V2)3m
After
2=0
0
SOLVE: For a package with mass m the conservation of energy equation is
K₁+U₁₁ = Ko+Um(vi)+mgy₁ =m(vo)+mgyo
Using (vo)m 0 m/s and y₁ =
m(v)
mgyo
0 m.
(vi)m =√29yo =√2(9.8 m/s²)(5.5 m) = 10.4 m/s
For the perfectly inelastic collision the conservation of momentum equation is
Piz Piz (m+2m)(v2)3mm(v1)m +(2m)(v1)2m
Using (1)2m 0 m/s, we get
(v2)3m = (v1)m 2m+m
(v1)
10.4 m/s
3
3
3.5 m/s
Suppose the collision between the packages is perfectly elastic. To what height does the package of mass m rebound?
Express your answer with the appropriate units.
▸ View Available Hint(s)
h=
2
HA
?
Units
Value
Transcribed Image Text:A package of mass m is released from rest at a warehouse loading dock and slides down the 5.5-m-high, frictionless chute to a waiting truck. Unfortunately, the truck driver went on a break without having removed the previous package, of mass 2m, from the bottom of the chute. (Figure 1) < 1 of 1 > Figure (vo)=0 yo Part B 7=0 Before (1)2m Om (V2)3m After 2=0 0 SOLVE: For a package with mass m the conservation of energy equation is K₁+U₁₁ = Ko+Um(vi)+mgy₁ =m(vo)+mgyo Using (vo)m 0 m/s and y₁ = m(v) mgyo 0 m. (vi)m =√29yo =√2(9.8 m/s²)(5.5 m) = 10.4 m/s For the perfectly inelastic collision the conservation of momentum equation is Piz Piz (m+2m)(v2)3mm(v1)m +(2m)(v1)2m Using (1)2m 0 m/s, we get (v2)3m = (v1)m 2m+m (v1) 10.4 m/s 3 3 3.5 m/s Suppose the collision between the packages is perfectly elastic. To what height does the package of mass m rebound? Express your answer with the appropriate units. ▸ View Available Hint(s) h= 2 HA ? Units Value
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