A parallel-plate capacitor has a capacitance of 660 pF, a plate area of 180 cm2, and a mica dielectric (K 5.40) completely filling the space between the plates. At 24.0 V potential difference, calculate (a) the electric field magnitude E in the mica, (b) the magnitude of the free charge on the plates, and (c) the magnitude of the induced surface charge on the mica.

Principles of Physics: A Calculus-Based Text
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ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter20: Electric Potential And Capacitance
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A parallel-plate capacitor has a capacitance of 660 pF, a plate area of 180 cm², and a mica dielectric (K = 5.40) completely filling the
space between the plates. At 24.0 V potential difference, calculate (a) the electric field magnitude E in the mica, (b) the magnitude of
the free charge on the plates, and (c) the magnitude of the induced surface charge on the mica.
%3D
(a) Number
Units
(b) Number
i
Units
(c) Number
i
Units
>
>
Transcribed Image Text:A parallel-plate capacitor has a capacitance of 660 pF, a plate area of 180 cm², and a mica dielectric (K = 5.40) completely filling the space between the plates. At 24.0 V potential difference, calculate (a) the electric field magnitude E in the mica, (b) the magnitude of the free charge on the plates, and (c) the magnitude of the induced surface charge on the mica. %3D (a) Number Units (b) Number i Units (c) Number i Units > >
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