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- An object is initially moving in the x-direction at 2.9 m/s when it undergoes acceleration in the y-direction for a period of 14 s. If the object moves equal distances in the x- and y-directions during this time, what’s the magnitude of its acceleration?At t = 0 the coordinates of a particle are x = 0, y = 2.10 m. At a time 1.05 s later, its coordinates are x = 2.94 m, y = 3.80 m. Find the components of the particle's average velocity during this time interval. vx = ? vy = ?In a particular Cartesian coordinate system, the y and z-components of the acceleration are zero and the x-component varies as given by the following function: ax(t) = 8t - 2t2 + 15e-t/F, where t is in seconds, ax is in meters per square second, and the constant F is in seconds. At t = 0, the particle was at position x = 3 m with a velocity pointing towards the positive x-axis and having magnitude 25 m/s. In the following problem you can take the constant F = 1.0 s.
- An object is moving in the negative y-direction at 20.0 m/s when it undergoes an acceleration a → = ( 1.00 m / s 2 ) i ^. What is the speed (magnitude of velocity) of the object 10.0 s later?Most important in an investigation of an airplane crash by the U.S. National Transportation Safety Board is the data stored on the airplane’s flight-data recorder, commonly called the “black box” in spite of its orange coloring and reflective tape.The recorder is engineered to withstand a crash with an average deceleration of magnitude 3450 g during a time interval of 6.49 ms. In such a crash, if the recorder and airplane have zero speed at the end of that time interval, what is their speed at the beginning of the interval?if an object has a constant x - component of velocity and suddenly experiences an acceleration at an sngle of 70 degrees in the x direction, does the x component of velocity change?
- A particle’s velocity along the x-axis is described byv(t) = A t + B t2,where t is in seconds, v is in meters per second, A = 1.06 m/s2, and B = -0.51 m/s3. What is the distance traveled, in meters, by the particle between times t0 = 1.0 s and t1 = 3.0 s?The position coordinate of a particle which is confined to move along a straight line is given by "x = 2t3 −24t + 6", where x is measured in meters from a convenient origin and t is in seconds. Determine (a) the time required for the particle to reach a velocity of 72 m/s from its initial condition at t = 0 s, (b) the acceleration of the particle when v = 30 m/s, and (c) the net displacement of the particle during the interval from t = 1 s to t = 4 s.Most important in an investigation of an airplane crash by the U.S. National Transportation Safety Board is the data stored on the airplane’s flight-data recorder, commonly called the “black box” in spite of its orange coloring and reflective tape.The recorder is engineered to withstand a crash with an average deceleration of magnitude 3400g during a time interval of 6.50 ms. In such a crash, if the recorder and airplane have zero speed at the end of that time interval, what is their speed at the beginning of the interval?
- A classic physics problem states that if a projectile is shot vertically up into the air with an initial velocity of 146 feet per second from an initial height of 89 feet off the ground, then the height of the projectile, h, in feet, t seconds after it's shot is given by the equation: h=−16t2+146t+89h=-16t2+146t+89 Find the two points in time when the object is 126 feet above the ground (to one decimal places). Answer: The object is 126 feet off the ground at the following times: (Enter your two answers separated by a comma. Round to ONE decimal places.)A classic physics problem states that if a projectile is shot vertically up into the air with an initial velocity of 146 feet per second from an initial height of 89 feet off the ground, then the height of the projectile, hh, in feet, tt seconds after it's shot is given by the equation: h=−16t2+146t+89h=-16t2+146t+89 Find the two points in time when the object is 126 feet above the ground (to one decimal places). Answer: The object is 126 feet off the ground at the following times: (Enter your two answers separated by a comma. Round to ONE decimal places.)At an air show, a jet plane has velocity components vx= 695km/h and v y =415km/h at time 4.35 s and v x =938km/h and V y =365km/h at time 7.52s. A)For this time interval, find the xxx component of the plane's average acceleration. b)For this time interval, find the yyy component of the plane's average acceleration. C)For this time interval, find the magnitude of its average acceleration. D)For this time interval, find the direction of its average acceleration.