Need asap pls. A partiele with a charge of 1.24x10 Cis moving with instantaneous velocity v=(4.19x10*m/s)i +(-3.85x10*m/s)j. What is the force exerted on this particle by amagnetic field (a) B = (1.47)t and (b)B = (14T)k?%3D

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A particle with a charge of 1.24x10-Cis moving with instantaneous velocity v = (4.19x10*m/s)t+(-3.85x10*m/s)}. What is the force exerted on this particle by a magnetic field (a) B = (1.4T)t and (b) B = (1.47)k? %3D

A particle with a charge of 1.24x10-Cis moving with instantaneous velocity v = (4.19x10m/s)t+(-3.85x10m/s)}. What is the force exerted on this particle by a magnetic field (a) B = (1.4T)t and (b) B = (1.47)k? %3D

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter11: Magnetic Forces And Fields

Section: Chapter Questions

Problem 6CQ: If a charged particle moves in a straight line, can you conclude that there is no magnetic field...

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Concept explainers

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.

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Need asap pls.

A partiele with a charge of 1.24x10 Cis moving with instantaneous velocity v=
(4.19x10*m/s)i +(-3.85x10*m/s)j. What is the force exerted on this particle by a
magnetic field (a) B = (1.47)t and (b)B = (14T)k?
%3D

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