A particle with positive charge q = 1.92 x 10-18 C moves with a velocity v = (51+ 41 - k) m/s through a region where both a uniform magnetic field and a uniform electric field exist. (a) Calculate the total force on the moving particle, taking B = (51 + 5ĵ + k) T and Ể = (31 - 1 - 2k) V/m. (Give your answers in N for each component.) F = 2.3040E-17 ✔N Fy = -2.1120E-17 ✔N F₂ = -1.3440E-17 X How does the magnetic force depend on the velocity of the charge? N (b) What angle does the force vector make with the positive x-axis? (Give your answer in degrees counterclockwise from the +x-axis.) 47.3749 X You appear to have correctly calculated this angle using your incorrect results from part (a).° counterclockwise from the +x-axis (c) What If? For what vector electric field would the total force on the particle be zero? (Give your answers in V/m for each component.) Ex V/m V/m V/m Ę₂ =

Principles of Physics: A Calculus-Based Text
5th Edition
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Author:Raymond A. Serway, John W. Jewett
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Chapter22: Magnetic Forces And Magnetic Fields
Section: Chapter Questions
Problem 63P
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If you can help me with the rest of part a, b, and c id greatly appreciate it. Thank you.

A particle with positive charge q = 1.92 x 10-18 C moves with a velocity v = (51+ 41 - k) m/s through a region where both a uniform magnetic field and a uniform electric field exist.
(a) Calculate the total force on the moving particle, taking B = (51 + 5ĵ + k) T and Ể = (31 - 1 - 2k) V/m. (Give your answers in N for each component.)
F = 2.3040E-17
✓✔N
Ty
= -2.1120E-17
✔ N
-1.3440E-17
X
How does the magnetic force depend on the velocity of the charge? N
(b) What angle does the force vector make with the positive x-axis? (Give your answer in degrees counterclockwise from the +x-axis.)
47.3749
x
You appear to have correctly calculated this angle using your incorrect results from part (a).° counterclockwise from the +x-axis
(c) What If? For what vector electric field would the total force on the particle be zero? (Give your answers in V/m for each component.)
E₂ =
V/m
V/m
V/m
Ev=
E₂
Transcribed Image Text:A particle with positive charge q = 1.92 x 10-18 C moves with a velocity v = (51+ 41 - k) m/s through a region where both a uniform magnetic field and a uniform electric field exist. (a) Calculate the total force on the moving particle, taking B = (51 + 5ĵ + k) T and Ể = (31 - 1 - 2k) V/m. (Give your answers in N for each component.) F = 2.3040E-17 ✓✔N Ty = -2.1120E-17 ✔ N -1.3440E-17 X How does the magnetic force depend on the velocity of the charge? N (b) What angle does the force vector make with the positive x-axis? (Give your answer in degrees counterclockwise from the +x-axis.) 47.3749 x You appear to have correctly calculated this angle using your incorrect results from part (a).° counterclockwise from the +x-axis (c) What If? For what vector electric field would the total force on the particle be zero? (Give your answers in V/m for each component.) E₂ = V/m V/m V/m Ev= E₂
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