A physics student uses a rod of an unknown length to demonstrate a physical pendulum. The period of oscillation of the rod is T = 2.20 seconds and the pivot point is located at a distance d= L/4 meters, where L is the unknown length of the rod. Find the length L of the rod if the Moment of Inertia of the rod is I = 0.15 ML² (kg•m²), where M is the mass of the rod and L is the unknown length of the rod.

Physics for Scientists and Engineers
10th Edition
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter15: Oscillatory Motion
Section: Chapter Questions
Problem 23P: A watch balance wheel (Fig. P15.25) has a period of oscillation of 0.250 s. The wheel is constructed...
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A physics student uses a rod of an unknown length to demonstrate a physical pendulum. The period of oscillation of the rod is T =
2.20 seconds and the pivot point is located at a distance d= L/4 meters, where L is the unknown length of the rod. Find the length L
of the rod if the Moment of Inertia of the rod is I = 0.15 ML² (kg•m²), where M is the mass of the rod and L is the unknown length of
the rod.
Transcribed Image Text:A physics student uses a rod of an unknown length to demonstrate a physical pendulum. The period of oscillation of the rod is T = 2.20 seconds and the pivot point is located at a distance d= L/4 meters, where L is the unknown length of the rod. Find the length L of the rod if the Moment of Inertia of the rod is I = 0.15 ML² (kg•m²), where M is the mass of the rod and L is the unknown length of the rod.
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