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A piece of metal with a specific heat of 0.57 J g-1°C-1 at 1188 °C is dunked into a beaker containing 369.7 mL of water at 25.1° by 14.5 °C. Assuming all heat is absorbed by the water, what was the mass (expressed in grams) of the metal? Cwater = 4.184 J9¬1°C-1 Puater = 1 g/mL Answer in decimal form with 1 decimal place

A piece of metal with a specific heat of 0.57 J g-1°C-1 at 1188 °C is dunked into a beaker containing 369.7 mL of water at 25.1° by 14.5 °C. Assuming all heat is absorbed by the water, what was the mass (expressed in grams) of the metal? Cwater = 4.184 J9¬1°C-1 Puater = 1 g/mL Answer in decimal form with 1 decimal place

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 20E: A 45-g aluminum spoon (specific heat 0.88 J/g C) at 24 C is placed in 180 mL (180 g) of coffee at 85...
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A piece of metal with a specific heat of 0.57 Jg-1°C-1 at 1188 °C is dunked into a beaker containing 369.7 mL of water at 25.1 °C. It raised the water's temperature by 14.5 °C. Assuming all heat is absorbed by the water, what was the mass (expressed in grams) of the metal? Cwater = 4.184J9-1°C-1 Pwater = 1 g/mL Answer in decimal form with 1 decimal place
Transcribed Image Text:A piece of metal with a specific heat of 0.57 Jg-1°C-1 at 1188 °C is dunked into a beaker containing 369.7 mL of water at 25.1 °C. It raised the water's temperature by 14.5 °C. Assuming all heat is absorbed by the water, what was the mass (expressed in grams) of the metal? Cwater = 4.184J9-1°C-1 Pwater = 1 g/mL Answer in decimal form with 1 decimal place
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