Part A The forensic technician at a crime scene has just prepared a luminol stock solution by adding 12.0 g of luminol into a total volume of 75.0 mL of H2O. What is the molarity of the stock solution of luminol? Express your answer with the appropriate units. > View Available Hint(s) ? molarity of luminol solution = Value Units

Part A The forensic technician at a crime scene has just prepared a luminol stock solution by adding 12.0 g of luminol into a total volume of 75.0 mL of H2O. What is the molarity of the stock solution of luminol? Express your answer with the appropriate units. > View Available Hint(s) ? molarity of luminol solution = Value Units

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter13: Titrations In Analytical Chemistry

Section: Chapter Questions

Problem 13.4QAP

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Please help me find weight percentage of the unknown solution, Thank you in advance Data attached below: Data of unknown NaCl solution (by weight) weight of weighing bottle and solution: 34.91g weight of weighing bottle: 23.91g weight of the solution: 11.00g Initial buret reading 33.28ml Final buret reading: 43.26ml The volume of the solution; 9.98 ml The density of solution: 1.10 Weight % of unknow solution: ?
KHP (aq)+NaOH (aq)-->NaKHP (aq)+H2O(l) Trial Vi (mL) Vf (mL) 1 36.19 48.56 2 3 A student masses out 1.096 grams of KHP, which is dissolved in 25.00 mL of DI water. This KHP solution is titrated with NaOH, as shown in the equation above. Calculate the molarity of the NaOH solution.
Please answer this NEATLY, COMPLETELY, and CORRECTLY for an UPVOTE. From the stock solution (0.020 M), pipet 4.00 mL and dilute to 100.00 mL. From the diluted solution, pipet 0.00, 1.00, 1.50, 2.00, 2.50, 5.00 and 7.50 mL aliquots into 100 mL volumetric flasks. Dilute to mark. Determine the concentration of each standard solution and tabulate.
The aluminum in a 1.200-g sample of impure ammonium aluminum sulfate was precipitated with aqueous ammonia as the hydrous Al2O3.xH2O. The precipitate was filtered and ignited at to give anhydrous Al2O3, which weighed 0.2001 g. Express the result of this analysis in terms of %NH4Al(So4)2 %Al2O3 %Al
An unknown sample containing a mixture of NaCl and Na2CO3 was analyzed to determine the % composition of each compound. In the analysis for Na2CO3 (soda ash), the following data were obtained mass of unknown - 0.4436 g conc. of HCl used - 0.25 N initial volume - 0.5 mL final volume - 20.0 mL (MW soda ash) 106.12) 1.) What method was used to determine the concentration of HCl? 2.) What is the net volume of HCl used in the titration? 3.) What is % Na2CO3 in the given sample? NOTE: Round off your answer to a whole number (2 sig fig)
500mM K2Cr2O7 solution (0.500 mol/L) About 36.775 g of K2Cr2O7 (MM = 294.20 g/mol) was weighed on an analytical balance on an analytical balance. It was quantitatively transferred to a 250 mL volumetric flask, dissolved with distilled water, completed the volume is up to the mark and homogenized. How many milliliters (total) of the stock solution was used to prepare these solutions from the previous question?
Q. If we are asked to use the recorded Wright of copper(II)sulfate pentahydrate to calculate the exact concentration of of an experimentally recorded copper II sulfate in volumetric flask, do we multiply the grams of copper II sulfate by the molar mass to get the molarity of the copper? Then, do we use the dilution formula to get the concentration. The recorded mass was 2.493 g for 50ml of copper II sulfate stock solution.
and Employees CH STATE GE 90 ENDULERSE IS FOREVER "ON-Tame Name Jodi Rayal Molarity = wt. x1000 3. Calculate the massof Potassium hydrogen phthalate (KHP) to prepare a 250.0 mL solution of 0.1000 M KHP solution. Mol ut. x Voluse the 2500×1000 204.22250 mass Initial Buret Reading Final Buret Reading Vol NaOH Added Moles of NaOH Moles of HCI Volume of unknown HCI solution Concentration of HCI Average concentration of HCI of KHP = 5.11g 4. Complete the table below for the following neutralization reaction of an unknown concentration of hydrochloric acid with 0.100 M sodium hydroxide: Mu spate solution Trial 1 0 11.15 го data and calculate the concentration 15 Trial 2 11.15 22.15 Trial 3 22.15 33.25 abyh 067 LANDINUKASHU TROWTHCENTISSATE ARAD Ma That par މއކނި REMURNAR MISAMARALISERDRY Tile
By pipet, 5.00 mLmL of a 0.823 MM stock solution of potassium permanganate (KMnO4) was transferred to a 50.00-mL volumetric flask and diluted to the calibration mark. Determine the molarity of the resulting solution.
In the standardization of HCl using pure anhydrous sodium carbonate as the primarystandard for methyl orange as an indicator, 1.0 mL HCl was found to be equivalent to 0.05gof sodium carbonate (MW =106). The normality of HCl is:
Mark and John, two vinegar enthusiasts, are each tasked to determine the acetic acid content of their respective vinegar concoctions by titration. First, a 1 M-labeled KOH solution was standardized against the KHP (MW = 204.22 g/mol) standard that is 99.4% pure. In the process, 0.540 g KHP was found to require 2.80 mL of the KOH solution to completely react up to the phenolphthalein endpoint. Then, Mark and John both prepared their samples by taking 10.0-mL aliquots of each vinegar and diluting them to 25.0 mL. Using the same titrant and indicator, Mark’s vinegar required 18.60 mL of the standardized titrant to reach the endpoint, while John’s vinegar required 16.50 mL of the same titrant to reach the same endpoint. Question: What is the acetic acid concentration of Mark’s and John’s vinegar in molarity given that the Concentration of KOH is 9386 M?
Mark and John, two vinegar enthusiasts, are each tasked to determine the acetic acid content of their respective vinegar concoctions by titration. First, a 1 M-labeled KOH solution was standardized against the KHP (MW = 204.22 g/mol) standard that is 99.4% pure. In the process, 0.540 g KHP was found to require 2.80 mL of the KOH solution to completely react up to the phenolphthalein endpoint. Then, Mark and John both prepared their samples by taking 10.0-mL aliquots of each vinegar and diluting them to 25.0 mL. Using the same titrant and indicator, Mark’s vinegar required 18.60 mL of the standardized titrant to reach the endpoint, while John’s vinegar required 16.50 mL of the same titrant to reach the same endpoint. Question: What is the exact concentration of the KOH titrant in molarity? What is the balanced chemical equation between the analyte and the titrant? What is the color transition (color X ? color Y) expected throughout the course of titration?