(a) Plot the data as engineering stress versus engineering strain. (b) Compute the modulus of elasticity. (c) Determine the yield strength at a strain offset of 0.002.
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- Following experimental data are obtained from tensile test of a rectangular test specimen with original thickness of 2,5 mm, gauge width of 24 mm and gauge length of 101 mm: Load (N) Elongation (mm) 0 0 24372 0,183 23008 0,315 28357 5,777 35517 12,315 27555 17,978 23750 23,865 Based on the information above; draw stress-strain diagram of the material and answer the following questions. - Determine the true stress (in MPa) at yield point. - Determine the true stress (in MPa) at point of ultimate strength. - Determine the true stress (in MPa) at fracture point. - Determine the true strain (in mm/mm) at yield point. (Use at least five decimal units) - Determine the true strain (in mm/mm) at point of ultimate strength. (Use at least five decimal units) - Determine the true strain (in mm/mm) at fracture point. (Use at least five decimal units)Following experimental data are obtained from tensile test of a rectangular test specimen with original thickness of 2,5 mm, gauge width of 24 mm and gauge length of 101 mm: Load (N) Elongation (mm) 0 0 24372 0,183 23008 0,315 28357 5,777 35517 12,315 27555 17,978 23750 23,865 Based on the information above; draw stress-strain diagram of the material and answer the following questions. Question 1 ;Determine the elastic energy absorption capacity (in N.mm) of that specimen. Question 2; Determine the plastic energy absorption capacity (in N.mm) of that specimen.I want answers to all four questions if possible. Thanks for help :) Following experimental data are obtained from tensile test of a rectangular test specimen with original thickness of 2,5 mm, gauge width of 24 mm and gauge length of 101 mm: Load (N) Elongation (mm) 0 0 24372 0,183 23008 0,315 28357 5,777 35517 12,315 27555 17,978 23750 23,865 Based on the information above; draw stress-strain diagram of the material and answer the following questions. - Calculate the fracture strength (in MPa) of the material. - Calculate the percent elongation of the specimen at fracture point. - Determine the modulus of resilience (in N.mm/mm3) of the material. (Use at least five decimal units) - Determine the toughness index number (in N.mm/mm3) of the material.
- The following results were obtained in a tensile test on a mild steel specimen of original diameter 28 mm and gauge length 56 mm. Load at limit of proportionality : 96 kN Extension at 96 kN load : 0.068 mm Load at yield point : 105 kN Maximum load : 170 kN When the two parts were fitted together after being broken, the length between gauge length was found to be 65.8 mm and the diameter at the neck was 18.8 mm. Calculate: (a). E, (b).σy, (c).σu, (d). PRIA and PE6. State your answers to the following questions.Strain Gauge represents the deformation of a material through a change in resistance. If so, explain how temperature will affect the strain gauge in the experimental environment.①:In this experiment, the Strain Gauge measures the strain in micro units. Explain one possible error factor when applying a load by hanging a weight on the material with the strain gauge attached. (Hint: It is easy to shake by hanging the weight using a thread)①:In a tensile test on a specimen of black mild steel of 12 mm diameter, the following results were obtained for a gauge length of 60 mm. Load W(kN) 5 10 15 20 25 30 35 40 Extension x (10-3 mm) 14 27.2 41 54 67.6 81.2 96 112 When tested to destruction. Maximum load = 65 kN; load at fracture = 50 kN, diameter at fracture = 7.5 mm, total extension on gauge length = 17 mm. Find young's modulus, specific modulus, ultimate tensile stress, breaking stress, true stress at fracture, limit of proportionality, percentage elongation, percentage reduction in area. The relative density of the steel is 7.8. Draw the straight line graph.
- In a tensile test on a specimen of black mild steel of 12 mm diameter, the following results were obtained for a gauge length of 60 mm. Load W(kN) 5 10 15 20 25 30 35 40 Extension x (10-3 mm) 14 27.2 41 54 67.6 81.2 96 112 When tested to destruction. Maximum load = 65 kN; load at fracture = 50 kN, diameter at fracture = 7.5 mm, total extension on gauge length = 17 mm. Find young's modulus, specific modulus, ultimate tensile stress, breaking stress, true stress at fracture, limit of proportionality, percentage elongation, percentage reduction in area. The relative density of the steel is 7.8. Draw the straight line graph. Answer: breaking stress,true stress at fracture and limit of proportionality.Manufacturing engineering- A single strain gauge is mounted to measure the axial strain in a simple tensile member the recorded strain is 200 microstrain, what is the axial stress ? a) If the member is of steel? b) if the member is of aluminium ? The modulus of elasticity of steel is 200 GPa and that of aluminium is 70 GPaA) An engineer works for a company that has many gray cast iron rods of different diameters and would like to design an equivalent rod that could handle a force of P= 10.0 kipkip without fracturing. What is the minimum diameter that this new rod must have to support P? B)A tensile test is being conducted on a steel-rod specimen with a gauge length of L0 = 4.0 in and an initial diameter of d0 = 0.75 in. If the final length of the rod at fracture is Lf= 5.53 in , find the percent elongation of the rod at fracture.
- An aluminium tensile test specimen has a diameter, d = 25 mm and a gauge length of Lo = 250 mm. If a force of 175 KN elongates the gauge length by 1.25 mm, the moduls of elasticity of the material is nearlyThe following data was obtained as a result of tensile testing of a standard 0.505 inch diameter test specimen of magnesium. After fracture, the gage length is 2.245 inch and the diameter is 0.466 inch. a). Calculate the engineering stress and strain values to fill in the blank boxes and plot the data. Load(lb) Gage Length (in) Stress (kpsi) Strain 0 2 1000 2.00154 2000 2.00308 3000 2.00462 4000 2.00615 5000 2.00769 5500 2.014 6000 2.05 6200 (max) 2.13 6000 (fracture) 2.255 b). Calculate the modulus of elasticity c). If another identical sample of the same material is pulled only to 6000 pounds and is unloaded from there, determine the gage length of the sample after unloading.A tension test was performed on a specimen having an original diameter of 12.5 mm and a gage length of 50mm. The data are listed in the table below: Complete the following: Plot the stress-strain curve. Label the y-axis every 50 MPa, and the x-axis every 0.05 mm/mm. Plot the linear portion of the stress-strain curve (first 5 points). Label the y-axis every 50 MPa, and the x-axis every 0.001 mm/mm. Determine the approximate Modulus of Elasticity Determine the approximate Ultimate Stress Determine the approximate Fracture Stress Determine the approximate Modulus of Resilience Determine the approximate Modulus of Toughness Other Requirements: Provide an example hand-written calculation showing how you calculated one point on the curve. Remember to properly label your plots and provide axis labels with units. Hand sketched plots will not be accepted. Use Excel or similar software.