QImagnitude of the torque he applies about the pipe at lower right?A plumber pushes straight down on the end of a long wrench as shown. What is theA. (0.80 m)(900 N)sin 19°B. (0.80 m)(900 N)cos 19°0.80 mC. (0.80 m)(9000 N)sin 19°F = 900 ND. (0.80 m)(90 N)cos 19°19°E. (0.80 m)(90 N)sin 19°

Force (F→) = -900j^L→ =0.8 (-cos19oi^ + sin19o j^)

A plumber pushes straight down on the end of a long wrench as shown. What is the QI magnitude of the torque he applies about the pipe at lower right? A. (0.80 m)(900 N)sin 19° B. (0.80 m)(900 N)cos 19° 0.80 m C. (0.80 m)(9000 N)sin 19° F= 900 N D. (0.80 m)(90 N)cos 19° 19 E. (0.80 m)(90 N)sin 19°

A plumber pushes straight down on the end of a long wrench as shown. What is the QI magnitude of the torque he applies about the pipe at lower right? A. (0.80 m)(900 N)sin 19° B. (0.80 m)(900 N)cos 19° 0.80 m C. (0.80 m)(9000 N)sin 19° F= 900 N D. (0.80 m)(90 N)cos 19° 19 E. (0.80 m)(90 N)sin 19°

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter10: Rotational Motion

Section: Chapter Questions

Problem 23P: Find the net torque on the wheel in Figure P10.23 about the axle through O, taking a = 10.0 cm and b...

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