A point charge +Q is located on the x axis at x = a, and a second point charge -Q is located onthe x axis at x = -a. A Gaussian surface with radius r = 2a is centered at the origin. The fluxthrough this Gaussian surface isSelect one:а.zero because the electric field is zero at every point on the surface.b.zero because the negative flux over one hemisphere is equal to the positive flux over theother.С.zero because at every point on the surface the electric field has no componentperpendicular to the surface.d.greater than zero.е.none of the above.

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A point charge +Q is located on the x axis at x = a, and a second point charge -Q is located on the x axis at x = -a. A Gaussian surface with radius r = 2a is centered at the origin. The flux through this Gaussian surface is Select one: O a. zero because the electric field is zero at every point on the surface. O b. zero because the negative flux over one hemisphere is equal to the positive flux over the other. с. zero because at every point on the surface the electric field has no component perpendicular to the surface. d. greater than zero. O e. none of the above.

A point charge +Q is located on the x axis at x = a, and a second point charge -Q is located on the x axis at x = -a. A Gaussian surface with radius r = 2a is centered at the origin. The flux through this Gaussian surface is Select one: O a. zero because the electric field is zero at every point on the surface. O b. zero because the negative flux over one hemisphere is equal to the positive flux over the other. с. zero because at every point on the surface the electric field has no component perpendicular to the surface. d. greater than zero. O e. none of the above.

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter24: Gauss’s Law

Section: Chapter Questions

Problem 24.63CP: A dosed surface with dimensions a = b= 0.400 111 and c = 0.600 in is located as shown in Figure...

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