A poll is given, showing 70% are in favor of a new building project. If 8 people are chosen at random, what is the probability that exactly 6 of them favor the new building project?

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Question 11
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C 0/1 pt 5 5 99
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A poll is given, showing 70% are in favor of a
new building project.
If 8 people are chosen at random, what is the
probability that exactly 6 of them favor the
new building project?
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Transcribed Image Text:8:43 + 76° 0. 5G4 50% LTI Launch blackboard.odessa.edu = X LTI Launch Review for Test 2 Score: 5/16 5/16 answered Progress saved Done Question 11 > C 0/1 pt 5 5 99 Details A poll is given, showing 70% are in favor of a new building project. If 8 people are chosen at random, what is the probability that exactly 6 of them favor the new building project? Submit Question Jump to Answer
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C 0/1 pt 5 5 99 O Details
The television show Green's Anatomy has been
successful for many years. That show recently
had a share of 17, which means, that among
the TV sets in use, 17% were tuned to Green's
Anatomy. An advertiser wants to verify that
17% share value by conducting its own survey,
and a pilot survey begins with 13 households
have TV sets in use at the time of a Green's
Anatomy broadcast.
Find the probability that none of the
households are tuned to Green's Anatomy.
P(none) =
Find the probability that at least one
household is tuned to Green's Anatomy.
P(at least one) =
%3D
Find the probability that at most one
household is tuned to Green's Anatomy.
P(at most one) =
If at most one household is tuned to Green's
Anatomy, does it appear that the 17% share
value is wrong? (Hint: Is the occurrence of at
most one household tuned to Green's Anatomy
unusual?)
Transcribed Image Text:8:43 + 76° 0. 5G4 50% LTI Launch blackboard.odessa.edu = X LTI Launch Question TZ C 0/1 pt 5 5 99 O Details The television show Green's Anatomy has been successful for many years. That show recently had a share of 17, which means, that among the TV sets in use, 17% were tuned to Green's Anatomy. An advertiser wants to verify that 17% share value by conducting its own survey, and a pilot survey begins with 13 households have TV sets in use at the time of a Green's Anatomy broadcast. Find the probability that none of the households are tuned to Green's Anatomy. P(none) = Find the probability that at least one household is tuned to Green's Anatomy. P(at least one) = %3D Find the probability that at most one household is tuned to Green's Anatomy. P(at most one) = If at most one household is tuned to Green's Anatomy, does it appear that the 17% share value is wrong? (Hint: Is the occurrence of at most one household tuned to Green's Anatomy unusual?)
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