A previous Chem 100 student carried out the experiment you did by reacting 0.036 g of magnesium. The following data was collected in their lab notebook. The water temperature was 19.8°C.  The barometer in the lab read 755.5 mm Hg and 31.97 mL of gas was collected The vapor pressure of water at this temperature is 17.32 mm Hg. Calculate the student’s experimental value of R. Report your answer to four places after the decimal.

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter5: Gases
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Problem 88QAP
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A previous Chem 100 student carried out the experiment you did by reacting 0.036 g of magnesium. The following data was collected in their lab notebook.

  • The water temperature was 19.8°C. 
  • The barometer in the lab read 755.5 mm Hg and
  • 31.97 mL of gas was collected
  • The vapor pressure of water at this temperature is 17.32 mm Hg.

Calculate the student’s experimental value of R. Report your answer to four places after the decimal.

Expert Solution
Step 1

       Barometer pressure         = 755.5 mm of HgTemperature of given solution = 19.8oC                                                     =(19.8 + 273.15)                                                     = 292.95K

Step 2

Vapour pressure of water = 17.32 mm Hg

              Gas pressure (P) = 760-17.32

                                         = 742.68 mm of Hg

          Given Mass of Mg =  0.036 g

Step 3

Moles of Mg = 0.03624                      = 1.5 ×10-3 moles\Consider a reaction Mg + 2HCl → MgCl2 + H2(g)

Step 4

1 mole of Mg produce 1 mole of H2 gas1.5 mole of Mg produce 1.5 mole of H2 gas          Moles of gas = 1.5×10-3 mol  volume of the gas= 31.97 mL                                 = 0.03197 L

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