A proton moving in a circular path perpendicular to a constant magnetic field takes 1.00 µs to complete one revolution. Determine the magnitude of the magnetic field. Taken as q = 1.602x10-19 C and m= 1.67x10-27 kg for proton and t=3.14.
A proton moving in a circular path perpendicular to a constant magnetic field takes 1.00 µs to complete one revolution. Determine the magnitude of the magnetic field. Taken as q = 1.602x10-19 C and m= 1.67x10-27 kg for proton and t=3.14.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter19: Magnetism
Section: Chapter Questions
Problem 8P: An oxygen ion (O+) moves in the xy-plane with a speed of 2.50 103 m/s. If a constant magnetic field...
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