A proton moving in a circular path perpendicular to a constant magnetic field takes 1.00 µs to complete one revolution. Determine the magnitude of the magnetic field. Taken as q = 1.602x10-19 C and m= 1.67x10-27 kg for proton and t=3.14.

College Physics
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Publisher:Raymond A. Serway, Chris Vuille
Chapter19: Magnetism
Section: Chapter Questions
Problem 8P: An oxygen ion (O+) moves in the xy-plane with a speed of 2.50 103 m/s. If a constant magnetic field...
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A proton moving in a circular path perpendicular to a constant magnetic field takes 1.00 us to
complete one revolution. Determine the magnitude of the magnetic field. Taken as q =
1.602x10-19 C and m = 1.67x1027 kg for proton and n=3.14.
O A) 0.0345 T
O B) 0.0143 T
C) 0.0124 T
D) 0.0154 T
E) 0.0327 T
Transcribed Image Text:A proton moving in a circular path perpendicular to a constant magnetic field takes 1.00 us to complete one revolution. Determine the magnitude of the magnetic field. Taken as q = 1.602x10-19 C and m = 1.67x1027 kg for proton and n=3.14. O A) 0.0345 T O B) 0.0143 T C) 0.0124 T D) 0.0154 T E) 0.0327 T
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