A proton (q = 1.602 × 10 °C) is moving with speed v of 5.50 × 10°m/s along the positive y-axis under a uniform magnetic field. The direction of the magnetic field is parallel to the yz-plane and it makes a 30° angle with the velocity of proton. (a) What is the direction of the magnetic force F, on the charge? Please draw Fg on the diagram below. (b) If the magnitude of the magnetic force FB on proton is 1.45 × 10-19N, then what is the magnitude of the magnetic field? BX 30

Principles of Physics: A Calculus-Based Text
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Chapter22: Magnetic Forces And Magnetic Fields
Section: Chapter Questions
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A proton (q = 1.602 × 10-19C) is moving with speed v of 5.50 x 10ºm/s along the positive y-axis under a
uniform magnetic field. The direction of the magnetic field is parallel to the yz-plane and it makes a 30° angle
with the velocity of proton.
(a) What is the direction of the magnetic force FB on the charge? Please draw Fp on the diagram below.
(b) If the magnitude of the magnetic force FB on proton is 1.45 x 10-19N, then what is the magnitude of the
magnetic field?
30
Transcribed Image Text:A proton (q = 1.602 × 10-19C) is moving with speed v of 5.50 x 10ºm/s along the positive y-axis under a uniform magnetic field. The direction of the magnetic field is parallel to the yz-plane and it makes a 30° angle with the velocity of proton. (a) What is the direction of the magnetic force FB on the charge? Please draw Fp on the diagram below. (b) If the magnitude of the magnetic force FB on proton is 1.45 x 10-19N, then what is the magnitude of the magnetic field? 30
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