A proton that has an instantaneous velocity of v=[2×10^6i+3×10^6j]m/s, is moving through the uniform magnetic field B=[0.03i−0.15k]T. Find the resultant magnetic force and its magnitude

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Chapter1: Physics And Measurement
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A proton that has an instantaneous velocity of v=[2×10^6i+3×10^6j]m/s, is moving through the uniform magnetic field B=[0.03i−0.15k]T. Find the resultant magnetic force and its magnitude

v=(2*10^6i+3*10^6j)m/s
B=(0.03i-0.15k)T
Transcribed Image Text:v=(2*10^6i+3*10^6j)m/s B=(0.03i-0.15k)T
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