A pulley-and-cable assembly supports block W and requires a downward force at P for equilibrium. Knowing that the tension of cable FG is 61.2 N, calculate the mass of the block and the magnitude of the downward force P.
A pulley-and-cable assembly supports block W and requires a downward force at P for equilibrium. Knowing that the tension of cable FG is 61.2 N, calculate the mass of the block and the magnitude of the downward force P.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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NOTE:
- Refer to the given sample problem below on how to solve the problem.
- The sub answers must be in 6 decimal places and the FINAL answer should be in 4 decimal places.
- Every part should have a free body diagram to show how you solved the problem.
- PLEASE FOLLOW MY INSTRUCTIONS. Thank you.
Transcribed Image Text:A pulley-and-cable assembly supports block W and requires a downward force at P for equilibrium. Knowing that the tension of cable FG is 61.2 N,
calculate the mass of the block and the magnitude of the downward force P.
A
ww
54"
L36*
78.701
25
w.
ww-
Transcribed Image Text:Sample Problem 9
The system shown is used to
support a 10lb Block and a
Block A. If the Tension in Cable O
2 is 5lb,
following:
a) WA weight of Block A
b) T, T3 tension at cables 1
and 3
10-lb
determine the T
60
45
c) x spring deformation (k =
30lb/ft)
2. Equilibrium of Particles
Sample Problem 9
Given:
T2 = 5lb
k = 30lb/ft
A10 Ib
60"
45
Required:
a) WA
b) T,, T3
c) x deformation of sering
2. Equilibrium of Particles
Sample Problem 9
* Consider A
31.
10 lb
60
45
-ST, cos 6o 1(5 )ws450
T :: 357o lb. T
3T, sınco + 54 5 sin a5-w-o
W, 3(1570)sinwo 1545sinus
W 14 6592 lo
2. Equilibrium of Particles
Sample Problem 9
* Consider the 10 l6 block
Principle of
Transomissibility
10 lb
60
45
-1, cos4s 1T30
1 Solve x
-5 sinys -10 - Fg:0
Fg= -15-535 N.T
F: 13 535S N,C
Tyi35 395 1b, T
-135355 : () *
x-0 4512 4
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