A random sample of 212 high school students in a particular town showed that 56 smoke on a regular basis. Find the 95% confidence interval estimating the population percentage for smokers at this high school. Suppose the national average for smokers in high schools is 34.2%. Does it appear that the students in this particular town smoke less than the national average?  Explain why.

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A: Given, n1 = 73 x1 = 10 n2 = 80 x2 = 16 confidence level = 1 - α = 0.95 α = 0.05α2 = 0.025   To find,…

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A: Formula :

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A: Given Information: Sample size (n) = 48  Mean Diameter (u) = 36.4 inches Standard Deviation (s) =…

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A: We have to find the length of confidence interval for the proportion.

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A: Here given  In a survey of 532 unemployed adults, 225 said that they had been unemployed for more…

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A:

Q: A Gallup poll of 1001 Americans age 18 and over conducted in May of 2013 found that 80% of the…

A: Solution: From the given information, p-hat=80% and the margin of error is 3.2%.

Q: A study is being planned by a pharmaceutical company to estimate the proportion of customers who…

A: We have given that,  Margin of error (E) = 3% = 0.03, confidence interval = 95%  Then,  We will find…

Q: A random sample of 240 adults over the age of 40 found that 144 would use an online dating service.…

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Q: A recent survey showed that from a sample of 500 packages delivered by a Postal Service, 480 were…

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Q: A random sample of 360 medical doctors showed that 106 had a solo practice. As a news writer, how…

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A: Hey, since there are multiple subparts posted, we will answer the first three subparts. If you want…

Q: The results of the National Health and Nutrition Examination Survey for the year 2011-12 found that…

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Q: In a survery of 1118 American adults, 626 said they drink  coffee over tea. What would be the 95%…

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A: The confidence level is 99%. For, 1-α=0.99α=0.01 Computation of critical value: The critical value…

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Q: how many students do we need to construct a 95% confidence interval for the proportion of the…

A: here given ,  margin of error  = 3% = 0.03  confidence level = 95%  n = 150  p^= 0.68

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A: A political candidate is anxious about the outcome of the next election. To have his next survey…

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A: Given 99% CI for population proportion of all students at this college is (0.78,0.98)

Q: survey of an urban university showed that 750 of 1,100 students sampled attended a home football…

A:

Q: The figure to the right shows the results of a survey in which 997 adults from Country​ A, 1022…

A: Given data For country A n = 997

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A: Given information Sample size (n) = 200

Q: A survey of 95 families showed that 40 of the families owned at least one tv. a. Find the 90%…

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Q: In a random sample of 250 students who enrolled in Science, 150 took notes during classes. Find an…

A: Given that n=250,x =150,alpha =0.05 Find an approximate 95% confidence interval for the population…

Q: Based on a sample of 1000 adult Americans, USA Today reported that 840 of them preferred cheese on…

A: Given that on a sample of 1000 adult Americans, USA Today reported that 840 of them preferred…

Q: A random sample of 328 medical doctors showed that 171 had a solo practice. Let p represent the…

A: Given, The best point estimate for p is,

Q: A survey of 240 teachers found that two-thirds of those surveyed do not live in Sydney. Can you…

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Q: A certain article indicates that in a sample of 1,000 dog owners, 660 said that they take more…

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Q: According to some car loan statistics, 44% of Americans are relying on an auto loan to pay for their…

A: Givenp^=0.44sample size(n)=1500confidence interval = 95%

Q: A college alumni Organization sent a survey to all recent graduates to ask their annual income. 20%…

A: Given, All recent graduates of a college were asked their annual income for a survey that was…

Q: A recent provincial report states that 90% of the population is aware that piercings as well as…

A:

Q: According to a report on sleep deprivation by the Centers for Disease Control and Prevention, the…

A: Given that  p^1=7.8%=0.078p^2=8.7%=0.087n1=11937n2=4892p^=n1p^1+n2p^2n1+n2=0.0806 Confidence…

Q: A local health centre noted that in a sample of 400 patients, 80 were referred to them by the local…

A:

Q: In a survey of a random sample of 49 college students, the sample mean time per week spent watching…

A: Given Sample size n=49, sample mean x̄=21, standard deviations s=6.2

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.