A random sample of 38 taxpayers claimed an average of $9,808 in medical expenses for the year. Assume the population standard deviation for these deductions was $2,411. Construct confidence intervals to estimate the average deduction for the population with the levels of significance shown below. a. 1% b.5% c. 20% a. The confidence interval with a 1% level of significance has a lower limit of $ 8,801 and an upper limit of $ 10,815. (Round to the nearest dollar as needed.) b. The confidence interval with a 5% level of significance has a lower limit of and an upper limit of $ $ (Round to the nearest dollar as needed.)

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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A random sample of 38 taxpayers claimed an average of $9,808 in medical
expenses for the year. Assume the population standard deviation for these
deductions was $2,411. Construct confidence intervals to estimate the average
deduction for the population with the levels of significance shown below.
a. 1%
b.5%
c. 20%
a. The confidence interval with a 1% level of significance has a lower limit of
$ 8,801 and an upper limit of $ 10,815.
(Round to the nearest dollar as needed.)
b. The confidence interval with a 5% level of significance has a lower limit of
$
and an upper limit of $
(Round to the nearest dollar as needed.)
Transcribed Image Text:A random sample of 38 taxpayers claimed an average of $9,808 in medical expenses for the year. Assume the population standard deviation for these deductions was $2,411. Construct confidence intervals to estimate the average deduction for the population with the levels of significance shown below. a. 1% b.5% c. 20% a. The confidence interval with a 1% level of significance has a lower limit of $ 8,801 and an upper limit of $ 10,815. (Round to the nearest dollar as needed.) b. The confidence interval with a 5% level of significance has a lower limit of $ and an upper limit of $ (Round to the nearest dollar as needed.)
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