A reaction was shown to follow second- order kinetics. How much time is required for [A] to change from 0.500 M to 0.240 M? (k = 0.456 M-¹ s¯¹)
A reaction was shown to follow second- order kinetics. How much time is required for [A] to change from 0.500 M to 0.240 M? (k = 0.456 M-¹ s¯¹)
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter18: Chemical Kinetics
Section: Chapter Questions
Problem 70AP
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Question
![6:29 PM Sun Feb 5
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A reaction was shown to follow second-
order kinetics. How much time is required
for [A] to change from 0.500 M to 0.240
M? (k = 0.456 M-¹s¯¹)
@
2
#
3
$
4
%
675
***
Question 32 of 50
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Transcribed Image Text:6:29 PM Sun Feb 5
Tap here or pull up for additional resources
A reaction was shown to follow second-
order kinetics. How much time is required
for [A] to change from 0.500 M to 0.240
M? (k = 0.456 M-¹s¯¹)
@
2
#
3
$
4
%
675
***
Question 32 of 50
6
&
7
8
Expert Solution
Step 1
Second order rate law is
where [A] = concentration after time t.
[A]0 = initial concentration.
k = rate constant.
t = time
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