A recent broadcast of a television show had a 1515 share, meaning that among 60006000 monitored households with TV sets in use, 1515% of them were tuned to this program. Use a 0.01 significance level to test the claim of an advertiser that among the households with TV sets in use, less than 2020% were tuned into the program. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method. Use the normal distribution as an approximation of the binomial distribution. Identify the null and alternative hypotheses. Choose the correct answer below. A. H0: pequals=0.800.80 H1: pgreater than>0.800.80 B. H0: pequals=0.800.80 H1: pless than<0.800.80 C. H0: pequals=0.800.80 H1: pnot equals≠0.800.80 D. H0: pequals=0.200.20 H1: pgreater than>0.200.20 E. H0: pequals=0.200.20 H1: pless than<0.200.20 Your answer is correct. F. H0: pequals=0.200.20 H1: pnot equals≠0.200.20 The test statistic is zequals=nothing.
A recent broadcast of a television show had a 1515 share, meaning that among 60006000 monitored households with TV sets in use, 1515% of them were tuned to this program. Use a 0.01 significance level to test the claim of an advertiser that among the households with TV sets in use, less than 2020% were tuned into the program. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method. Use the normal distribution as an approximation of the binomial distribution. Identify the null and alternative hypotheses. Choose the correct answer below. A. H0: pequals=0.800.80 H1: pgreater than>0.800.80 B. H0: pequals=0.800.80 H1: pless than<0.800.80 C. H0: pequals=0.800.80 H1: pnot equals≠0.800.80 D. H0: pequals=0.200.20 H1: pgreater than>0.200.20 E. H0: pequals=0.200.20 H1: pless than<0.200.20 Your answer is correct. F. H0: pequals=0.200.20 H1: pnot equals≠0.200.20 The test statistic is zequals=nothing.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
A recent broadcast of a television show had a
normal distribution as an approximation of the binomial distribution.
1515
share, meaning that among
60006000
monitored households with TV sets in use,
1515%
of them were tuned to this program. Use a 0.01 significance level to test the claim of an advertiser that among the households with TV sets in use, less than
2020%
were tuned into the program. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method. Use the Identify the null and alternative hypotheses. Choose the correct answer below.
H0:
pequals=0.800.80
H1:
pgreater than>0.800.80
H0:
pequals=0.800.80
H1:
pless than<0.800.80
H0:
pequals=0.800.80
H1:
pnot equals≠0.800.80
H0:
pequals=0.200.20
H1:
pgreater than>0.200.20
H0:
pequals=0.200.20
H1:
pless than<0.200.20
H0:
pequals=0.200.20
H1:
pnot equals≠0.200.20
The test statistic is
zequals=nothing.
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