A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll  n= 947 and x= 580 who said yes. Use a 99% confidence level . A) Find the best point of estimate of the population proportion p. B) Identify the value of the margin error E C) construct the confidence interval

Q: Use the confidence interval to find the margin of error and the sample mean. (0.558,0.740)

A: Given: confidence interval ( 0.558 , 0.74 ) Need to find sample mean(x̄) and margin of error(ME) .

Q: Use the Student's t distribution to find t, for a 0.95 confidence level when the sample is 27.

A: sample size=n=27 Degree of Freedom=n-1=27-1 =26 Confidence level is 0.95 Therefore the Level of…

Q: Construct the 99% confidence interval estimate of the population proportion p if the sample size is…

A: Obtain the 99% confidence interval estimate of the population proportion. The 99% confidence…

Q: and ˆpp^ (p-hat) =0.52, find the margin of error at a 99% confidence level Give your answer to…

A: The margin of error can be calculated as: MOE=z×p^(1-p^)n

Q: In a recent poll, 460 people were asked if they liked dogs, and 94% said they did. Find the margin…

A: Ans - Given   P  =  94%    = 0.94,     The sample size  n = 460 people          95%  confidence…

Q: The confidence interval was (52, 62) What was the point estimate? What was the margin of error?…

A:

Q: Use the confidence interval to find the margin of error and the sample mean. (1.52,2.06)

A: Given: Confidence interval is (1.52, 2.06) To determine: The margin error and The sample mean.…

Q: A poll asked respondents if they felt vulnerable to identify theft. In the poll, n= 1000 and x= 501…

A:

Q: Use the confidence interval to find the margin of error and the sample mean. (1.71, 1.99)

A: Solution:  Given data: confidence Interval = (1.71, 1.99) To find: 1.Margin of error 2. Sample mean…

Q: Use the given confidence interval to find the margin of error and the sample mean. .734, .760

A: From the given information, the confidence interval is (0.734, 0.760). It can be expressed in,

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll,…

A:

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll,…

A: Given that : n = 1072 x = 537 (a) to find the best point estimate of the population proportion p. P^…

Q: Use the given confidence interval to find the margin of error and the sample proportion. (0.704,…

A: The confidence interval for population proportion is given by (0.704, 0.732)

Q: Use the confidence interval to find the margin of error and the sample mean. (0.578,0.740)

A: Suppose the confidence interval is given as : (a,b) (x-MOE , x+MOE) = (0.578 , 0.740) Then to obtain…

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: From the provided information, Confidence interval is (0.751, 0.777)

Q: find the margin of error for a sample mean, given n=16, s=4, Xbar=17. for a 95% confidence interval.

A: The margin of error for sample mean is given by,

Q: Use the confidence interval to find the margin of error and the sample mean. (.228, 0.390)

A: We know that the Margin of error = (upper_limit - lower_imit )/2 and Sample mean = (upper limit +…

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,…

A: Given information: x=586 n=1006

Q: If n=22, ¯xx¯(x-bar)=39, and s=6, find the margin of error at a 98% confidence level Give your…

A:

Q: Use the given confidence interval to find the margin of error and the sample mean. (15.3,22.3)

A: We have to find sample mean and margin of error..

Q: find the margin of error at a 95% confidence level

A: Formula for margin of error is,

Q: Use the given confidence interval to find the margin of error and the sample mean . (12.9, 20.1)

A: See the handwritten solution

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: Given data, Lower limit LL=0.621 Upper limit UL=0.651   Margin of error(E)=? Sample proportion p=?

Q: If n=23, ¯x(x-bar)=34, and s=8, find the margin of error at a 99% confidence level Give your answer…

A: Solution: From the given information, n=23, x-bar=34 and s=8. The confidence level is 0.99.

Q: If n=12, ¯xx¯(x-bar)=44, and s=5, find the margin of error at a 99% confidence level

A: Given: margin of error for a 99% confidence interval. n=12 x¯(x-bar)=44 s=5

Q: Use the confidence interval to find the margin of error and the sample mean.   (0.676,0.800)

A: The margin of error is the most common term which we use in a confidence interval. It is the degree…

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll,…

A:

Q: use the given sample data and confidence level. In each case, (a) find the best point estimate of…

A:

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,…

A:

Q: A research institute poll asked respondents if they acted to annoy a bad driver. In the poll, n=2320…

A: The random variable percentage of people who said they honked follows binomial distribution. The…

Q: If n=270 and ˆpp^ (p-hat) =0.59, find the margin of error at a 99% confidence level Give your…

A: Given  n=270, pcap=0.59, alpha=0.01 Zcritical=2.578 at alpha=0.01 We want to find margin of error

Q: If n=14, (x-bar)-33, and s=9, find the margin of error at a 98% confidence level Give your answer to…

A: We have given that, Sample mean (x̄) = 33, standard deviation (s)= 9 and sample size (n) = 14  Then,…

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: Plug in all the values in the formula, we get Therefore,

Q: If n=24, ¯xx¯ (x-bar)=50, and s=9, find the margin of error at a 95% confidence level (use at least…

A: Given,n=24x¯=50s=9degrees of freedom(df)=n-1df=24-1=23α=1-0.95=0.05α2=0.025t0.025(23)=2.069…

Q: Use the confidence interval to find the margin of error and the sample mean. (1.59,1.89)

A: Given data,Lower limit=1.59Upper limit=1.89Margin of error=?

Q: Use the given confidence interval to find the margin of error and the sample mean. (71.7, 87.3)

A:

Q: Find 90% confidence interval for the true proportion of all medical students who plan to work in a…

A: Given : Sample Size, n = 300 Number of successes, x = 30

Q: If n=25, 7(x-bar)=48, and s=4, find the margin of error at a 80% confidence level

A: The sample size is 25, sample mean is 48, and sample standard deviation is 4. The degrees of freedom…

Q: Use the given confidence interval to find the margin of error and the sample mean.  (4.81, 8.09)

A: The confidence interval is given by (4.81, 8.09)

Q: Determine the margin of error for the confidence interval for the proportion: 0.518 <p<0.774 The…

A: We have to find margin of error

Q: 19) A political survey had a margin of error of 4.25%. If the surveyor used a 90% confidence level…

A: Assume p-hat as 0.5, since no preliminary estimate is available.

Q: find the margin of error at a 90% confidence level

A: Given : n=330 , p-hat=0.28  , α=0.10 We want to find the margin of error at a 90% confidence level.

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,…

A: Given data n=1026 x=520 confidence interval=95%

Q: After surveying 625 potential voters polled, you find out that 325 support candidate X and 300…

A: The sample proportion confidence interval is, p^±Zp^(1-p^)nwhere, p^ = the sample proportion…

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: Given: Confidence interval = (0.705, 0.733) Thus, Lower limit = 0.705 Upper limit = 0.733

Q: Use the given confidence interval to find the margin of error and the sample mean. (13.5,21.9)

A: Given confidence interval (13.5, 21.9)

Q: If n=23, x(x-bar)=47, and s=3, find the margin of error at a 98% confidence level Give your answer…

A: Margin error is the difference between the estimated value and the original value. Here the critical…

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: Let the confidence interval for population proportion is (a, b) Margin of Error : E =b-a2 Sample…

Q: If n=10, ¯xx¯(x-bar)=44, and s=8, find the margin of error at a 80% confidence level

A:

Q: If n=17, (x-bar)=44, and s=8, find the margin of error at a 95% confidence level

A: The sample mean is 44 and standard deviation is 8.