urgent need help asap A researcher crosses mice with brown eyes and short tails, and the F1 progeny were recovered in the following numbers and phenotypicclasses:F1: 32 apricot, short : 30 brown, long : 139 brown, short : 9 apricot, longYou know the genes encoding these traits are autosomal, completely dominant and assort independently. You want to use a chi-squaretest to analyse these results.a) Give the expected number of individuals in the "brown, short" class.b) What is your null hypothesis for the chi-square test?c) You obtaind) Makina use of the appropriate genetic convention for naming alleles, give the genotype of any of the progeny in the "apricot, short"class.value of 8.59 for the chi-square test. What conclusion can you make from the results of the chi-square test?

The genes in a dihybrid cross give a ratio of 9:3:3:1.

A researcher crosses mice with brown eyes and short tails, and the F1 progeny were recovered in the following numbers classes: F1: 32 apricot, short : 30 brown, long : 139 brown, short : 9 apricot, long You know the genes encoding these traits are autosomal, completely dominant and assort independently. You want to use test to analyse these results. a) Give the expected number of individuals in the "brown, short" class. b) What is your null hypothesis for the chi-square test? c) You obtain a value of 8.59 for the chi-square test. What conclusion can you make from the results of the chi-square tes d) Molrine bing plleles give the W

A researcher crosses mice with brown eyes and short tails, and the F1 progeny were recovered in the following numbers classes: F1: 32 apricot, short : 30 brown, long : 139 brown, short : 9 apricot, long You know the genes encoding these traits are autosomal, completely dominant and assort independently. You want to use test to analyse these results. a) Give the expected number of individuals in the "brown, short" class. b) What is your null hypothesis for the chi-square test? c) You obtain a value of 8.59 for the chi-square test. What conclusion can you make from the results of the chi-square tes d) Molrine bing plleles give the W

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter15: Genomes And Genomics

Section: Chapter Questions

Problem 2QP: Hemophilia and color blindness are both recessive conditions caused by genes on the X chromosome. To...

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A researcher crosses mice with apricot eyes and long tails, and the F1 progeny were recovered in the following numbers and phenotypic classes:F1: 21 apricot, short : 30 brown, long : 19 brown, short : 110 apricot, longYou know the genes encoding these traits are autosomal, completely dominant and assort independently. You want to use a chi-square test to analyse these results.a) What is your null hypothesis for the chi-square test? b) You obtain a value of 11.33 for the chi-square test. What conclusion can you make from the results of the chi-square test? c) Give the expected number of individuals in the “apricot, long” class. d) Making use of the appropriate genetic convention for naming alleles, give the genotype of any of the progeny in the “apricot, long” class.
Two pure-breeding parents produced a heterozygous female offspring (AaBb) that was then testcrossed with an aabb male. The offspring produced from the testcross included 50 AaBb, 450 Aabb, 450 aaBb, 50 aabb individuals. Describe how you can tell if these two genes are linked or unlinked (What ratio would you expect to see from the testcross if they were not linked?). What were the genotypes of the original parents that produced the heterozygous female? What is the genetic map distance between the two genes?
Assume that three loci, each with two alleles (A and a, B and b, C and c), determine the difference in height between two homozygous strains of a plant. These genes are additive and equal in their effects on plant height. One strain (aa bb cc) is 10 cm in height. The other strain (AA BB CC) is 22 cm in height. The two strains are crossed, and the resulting F1 are interbred to produce F2 progeny. Give the phenotypes and the expected proportions of the F2 progeny.
A homozygous strain of corn that produces yellow kernels is crossed with another homozygous strain that produces purple kernels. When the F1 are interbred, 197 of the F2 are yellow and 153 are prurple. Give the genotypes of the yellow and purple F2 and propose a genetic model that explains the inheritance of these kernel colors in corn.
. Consider the imaginary trait, bristles with split-ends, a trait hypothesized to be X-linked dominant. In a cross, the P1 virgin females were homozygous wild type while the males had bristles with split-ends. The F1 84 males were all wild type while the 90 females all had split-ends. In addition, the data for the F2 generation revealed 26 wild type males, 35 wild type females, 29 split-end males and 40 split-end females. Is this what is to be expected? Use chi-square to prove your position.
In fruit flies, long wings (M) is dominant to miniature wings (m) and red eyes (B) is dominant to brown eyes (b). You testcross a long-winged, red-eyed fly (genotype Mm Bb) female to a mini-winged, brown-eyed male (genotype mm bb) and get the following progeny: 256 long wings, red eyes 261 mini wings, red eyes 240 long wings, brown eyes 243 mini wings, brown eyes Are these genes for wing length and eye color linked or unlinked? How do you know?
A researcher crosses mice with brown eyes and long tails, and the F1 progeny were recovered in the following numbers and phenotypic classes:F1: 6 apricot, short : 30 brown, long : 15 brown, short : 9 apricot, longYou know the genes encoding these traits are autosomal, completely dominant and assort independently. You want to use a chi-square test to analyse these results.a) Making use of the appropriate genetic convention for naming alleles, give the genotype of the male parent in this cross. b) What is your null hypothesis for the chi-square test? c) Give the expected number of individuals in the “brown, long” class. d) You obtain a value of 3.47 for the chi-square test. What conclusion can you make from the results of the chi-square test?
In rabbits grey hair is dominant to white & black eyes are dominant to red. -Cross 2 parents who are both heterozygous for both traits. 1st Question to answer ---- How many of the offspring could have grey hair & black eyes? 2nd Question to answer ---- How many of the offspring could have grey hair & red eyes? 3rd Question to answer ---- How many of the offspring could have white hair & black eyes? 4th Question to answer ---- How many of the offspring could have white hair & red eyes?
A pure strain of Mendel’s peas, dominant for all seven of his independently assorting genes, was testcrossed. (a) How many different kinds of gametes could each of the parents produce? (b) How many different gametes could the F1 produce? (c) If the F1, was testcrossed, how many phenotypes would be expected in the offspring and in what proportions? d) How many genotypes would be expected in the F2? (e) How many combinations of F1 gametes are theoretically possible (considering, e.g., AABBCCDDEEFFGG sperm nucleus x aabbccddeefigg egg nucleus a different combination than AABBCCDDEEFFGG egg nucleus x aabbccddeeflgg sperm nucleus)? (f) How many different kinds of matings could theoretically be made among the F2?
Consider the results of a three point linkage mapping testcross between a female (AaBbCc) and a male (aabbcc). Phenotype | no. Of progeny ABc 849 abC 820 Abc 58 aBC 60 AbC 102 aBc 98 ABC 6 abc 7 a) what is the correct order of the gene loci? ( which gene is in the middle) B) what was the configuration of recessive alleles in the triple heterozygous mother? (Use a cis-trans statement) C) calculate the map distances for each segment of the map.
In the fruit fly, recessive mutations in either of two independently assorting genes, brown and purple, prevent the synthesis of red pigment in the eyes. Thus, homozygotes for either of these mutations have brownish-purple eyes. However, heterozygotes for both of these mutations have dark red, that is, wild-type eyes. If such double heterozygotes are intercrossed, what kinds of progeny will be produced, and in what proportions?
Two true-breeding varieties of maize, one 11 cm high and the other 47 cm high were crossed and the resultant F1 hybrids were then crossed to generate the F2 . In the F2 there were a total of 13,923 plants with a continuous variation in heights between the two extremes and with only 3 plants as large as 47 cm high and 5 plants of 11 cm high.So What would be the size and genotype of the F1 from a cross between a true-breeding 11 cm plant and a true-breeding 47 cm plant?